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slavikrds [6]
3 years ago
5

Help help help me this has to be done quick

Mathematics
1 answer:
artcher [175]3 years ago
6 0
B. ft^2

Hope this helps!
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Johann wants to build a set of wood shelves using a piece of wood that is 83 ½ inches long. Each shelf is an equal length of 12
Oksanka [162]

Answer:

He'll be able to make 6 shelves.

Step-by-step explanation:

In order to know haw many shelves he can make we need to take the total amount of material and divide it by the amount of material required for each shelve. We have:

total amount = 83 1/2 inches = 83.5 inches

amount per shelve = 12 3/4 inches = 12.75 inches

amount of shelves = total amount/amount per shelve

amount of shelves = 83.5/12.75 = 6.55 shelves

Since he can't make half shelves he'll be able to make 6 shelves and have left over material.

3 0
2 years ago
Match each system of equations to its solution represented by an augmented matrix.
SCORPION-xisa [38]

Answer:

Step-by-step explanation:

7 0
2 years ago
You’re rectangular 12 feet long and 8 feet wide. Your friend’s rectangular vegetable garden 50 feet long and 10 feet wide are th
igor_vitrenko [27]

Answer:

No

Step-by-step explanation:

For shapes to be similar, their ratios of length-to-length and width-to-width must be the same. When you divide the larger length by the smaller length and the larger width by the smaller width, do you get the same number? No, so these rectangles are not similar.

5 0
3 years ago
Read 2 more answers
Which of the following shows the extraneous solution(s) to the logarithmic equation? log4 (x) + log4(x - 3) = log4 (-7x + 21)
Salsk061 [2.6K]
First join the log4 on the left:

log4( x*(x-3) = log4(-7x+21)

Then x = -7, works: -7*(-10)=70 = -7*(-7)+21

x=-3, 18 = 42, does not work

x=3 0=0 works,

However, when one puts x = -7 in the *original* exression, log4(-7) or log4(-10) do not exist (you know why?). So x= -7 is extraneous.

Now x=3 gives log4(0) on the left and right, which does not exist.

So, C is the answer, both are extraneous. Seem to work but indeed don't work in the *original* equation
 
6 0
3 years ago
Read 2 more answers
at the start of the shift your part counter reads 250 at the end of the shift the part counter reads 1075 how many parts did you
Luden [163]
This can be mathematically expressed to
 250 + X  = 1075
where X represents the parts you produce before the shift ends
Transpose 250 to the other side by subtracting each side by 250
Thus, it goes like this
X = 1075 - 250
X = 825

You produced 825 parts in the middle of the shift.

5 0
3 years ago
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