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Allisa [31]
3 years ago
6

Which pairs of triangles can be shown to be congruent using rigid motions?

Mathematics
2 answers:
sergeinik [125]3 years ago
6 0

Answer:

Not congruent; not congruent; congruent; congruent; not congruent; not congruent.

Step-by-step explanation:

The base of △ABC, BC, is 2 units.  The height of △ABC, extending from A to BC, is 3 units.  This means that any triangle congruent to this will have a base of 2 and a height of 3.

△MNP has a base of 2; however, its height (from M to NP) is 4 units.  Therefore they are not congruent.

△EFG has a base of 2 and a height of 4; it and △ABC are not congruent.

△STU has a base of 2 and a height of 3; it is congruent to △ABC.

△EFG has a base of 2 and a height of 4, just as △MNP; they are congruent.

Since △STU is congruent to △ABC, and we know that △EFG is not congruent to △ABC, we know that △EFG is not congruent to △STU.

Since △MNP is congruent to △EFG, and △EFG is not congruent to △STU, then △MNP is not congruent to △STU.

DanielleElmas [232]3 years ago
5 0

Answer:

Not Congruent: ABC and MNP , ABC and EFG , EFG and STU , STU and MNP.

Congruent: ABC and STU , EFG and MNP.

Step-by-step explanation:


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y^{2}+5y+25

Step-by-step explanation:

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Read 2 more answers
4x+(x-y/8)=17 and 2y+x-(5y+2/4)=2 by using elimination method
vladimir2022 [97]

Answer:

x=811/238, y=36/119. (811/238, 36/119).

Step-by-step explanation:

4x+(x-y/8)=17

2y+x-(5y+2/4)=2

-----------------------

4x+x-y/8=17

5x-y/8=17

40x-y=136

y=40x-136

------------------

2y+x-5y-2/4=2

2y-5y+x-1/2=2

-3y+x=2+1/2

-3y+x=4/2+1/2

-3y+x=5/2

-3(40x-136)+x=5/2

-120x+408+x=5/2

-119x=5/2-408

-119x=5/2-816/2

-119x=-811/2

119x=811/2

x=(811/2)/119

x=(811/2)(1/119)=811/238

y=40(811/238)-136

y=16220/119-136

y=36/119

x=811/238, y=36/119.

4 0
4 years ago
Please help me in the question of commission ! Grade - 9 . ​
AlladinOne [14]

Answer:

Step-by-step explanation:

Commission for  amount  Rs. 5,00,00 = \frac{2}{100}*500000

                                                               = 2* 5000

                                                               = Rs. 10,000

total commission = Rs. 32,000

Remaining commission = 32500 - 10000

                                      = Rs. 22500

Let remaining amount of the restaurant = Rs. x

Commission on Rs. x = 22500

3% of x = 22500

\frac{3}{100}*x=22500\\\\x=22500*\frac{100}{3}\\\\x = 7500*100

x = Rs. 750000

Price of the restaurant = 750000 + 500000

                                     =Rs . 1250000

7 0
3 years ago
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