Answer:
±12.323
Step-by-step explanation:
A study by the department of education of a certain state was trying to determine the mean SAT scores of the graduating high school seniors. The study examined the scores of a random sample of 238 graduating seniors and found the mean score to be 493 with a standard deviation of 97. Calculate the margin of error using the given formula. How could the results of the survey be made more accurate?
The formula for margin of Error =
±z × Standard deviation/√n
We are not given the confidence interval but let us assume the confidence interval = 95%
Hence:
z score for 95% confidence interval = 1.96
Standard deviation = 97
n = random number of samples = 238
Margin of Error = ± 1.96 × 97/√238
Margin of Error = ±12.323
Answer:
it is not true because 102 does not equal 17
Answer:
(a) According to the central limit theorem, the distributions of the sample means of sufficiently large samples randomly selected from a population with mean, μ and standard deviation, σ with replacement will be normally distributed
Therefore, given that the size of the population from which the samples were selected (34 petri dishes) is comparable the sizes of the samples, (16 and 18), therefore, the samples are approximately normal
Also given that the petri dishes were prepared with growth medium designed to increase the growth of microorganisms, with an expected amount of growth, the samples therefore came from approximately normal distributions
Step-by-step explanation:
The answer is y=-4/7x+7. You simply substitute in the given numbers. -4/7 for the slope (m) and 7 for the y-intercept (b).
