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Lelu [443]
3 years ago
14

What is 1258 rounded to the nearest hundred?

Mathematics
2 answers:
Murljashka [212]3 years ago
5 0

Answer:

  1300

Step-by-step explanation:

The number in the place to the right of the hundreds place is 5, in the tens place. That digit is greater than 4, so the rounding is to the next higher hundred: 1300.

cestrela7 [59]3 years ago
3 0

Answer:

1300

Step-by-step explanation:

1258 rounded to the nearest hundred is 1300.

1258 is more than 1250.

If it were to be rounded to the nearest tenth, the answer would be 1260.

However, it says rounded to the nearest hundredth.

Therefore, the answer would be 1300.

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A circle is centered at the point (5, -4) and passes through the point (-3, 2).
zepelin [54]

Answer:

(x-5)^2+(y+4)^2=100

Step-by-step explanation:

As we know the given points

Center = (5, -4)

and

Point on circle = (-3,2)

The distance between point on circle and center will give us the radius of circle

So,

The formula for distance is:

\sqrt{(x_{2}-x_{1} )^{2}+(y_{2}-y_{1})^{2}}\\Taking\ center\ as\ point\ 1\ and\ the\ other\ point\ as\ point\ 2\\d=\sqrt{(-3-5)^{2}+(2-(-4))^{2}}\\d=\sqrt{(-8)^{2}+(2+4)^{2}}\\d=\sqrt{(-8)^{2}+(6)^{2}}\\\\d=\sqrt{64+36}\\d=\sqrt{100} \\ d=10\\So\ the\ radius\ is\ 10

The standard form of equation of circle is:

(x-h)^{2}+(y-k)^{2}=r^{2}

where h and k are the coordinates of the center. So putting in the value:

(x-5)^{2}+(y-(-4))^{2}=(10)^{2}\\(x-5)^{2}+(y+4)^{2}=100

8 0
3 years ago
The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.
MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle =3\times\ side

3\times\ side =[tex]81\sqrt{3}

Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm

Thus from the diagram , Side AB=BC=AC= 27\sqrt{3} \ cm

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus \angle OBC = 30°

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2}  } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\

Thus ,apothem  OE= 13.5 cm

Now for radius,

We consider ΔOBE

cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB}  \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

4 0
3 years ago
What is (7 x 1)+(4x1/10)+ (6x1/1000 written as a decimal in standard form
Paul [167]

Answer:

7.406

Step-by-step explanation:

It is 7.406 because 7x1 is 7, 4/10 is 0.4, and 6/1000 is 0.006. If you add those together, you will get 7.406.

8 0
3 years ago
Read 2 more answers
Solve for x. 0.2x – 1.8 5 = 4.2​
spin [16.1K]

Answer:

<h2>x = 114</h2>

Step-by-step explanation:

0.2x – 1.8/5 = 4.2​

0.2x - 1.8 = 4.2 (5)

x =<u> 21 + 1.8 </u>

        0.2

x = 22.8 / 0.2

x = 114

4 0
3 years ago
An astronaut weighs 685 N on earth. What would the astronaut's weight (in FORCE) be on Jupiter where gravity= 25.9 m/s2? (*Tip:
VladimirAG [237]

Answer:

Step-by-step explanation:

I'm sure by now you have learned the difference between mass and weight. Mass will never change regardless of where something is while weight changes depending upon the pull of gravity. If we want the mass, then we have to take the weight on Earth and divide by its pull of gravity. The equation for that will be

W = mg where W is the weight in Newtons, m is mass and g is gravity.

685 = m(9.8) so

m = 7.0 × 10¹ kg

Now that we know that mass, and also because we know that the mass is constant no matter where the astronaut is, we can find his weight on Jupiter.

W = (7.0 × 10¹)(25.9) so

W = 1800 N

3 0
2 years ago
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