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Juliette [100K]
4 years ago
11

For a recent year, the number of men in the U.S Senate totaled 4 more than five times the number of woman. Find the number of me

n and the number of women in the U.S Senate which has a total of 100 members
Mathematics
1 answer:
algol134 years ago
8 0

Answer:

There are 84 men and 16 women in the U.S Senate.

Step-by-step explanation:

We are given the following in the question:

Let x be the number of males and y be the number of females.

Total members = 100

Thus, we can write the equation:

x + y = 100

Men in the U.S Senate totaled 4 more than five times the number of woman.

Thus, we can write the equation:

x = 4 + 5y

Solving the two equations by substitution method, we have,

(4+5y) + y = 100\\\Rightarrow 4 + 6y = 100\\\Rightarrow 6y = 96\\\Rightarrow y = 16\\\Rightarrow x = 4 + 5(16) = 84

Thus, there are 84 men and 16 women in the U.S Senate.

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If you add 21 to my number and then multiply the result by 3, you will get 84 more than two-thirds of my number. Find my number.
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Based on the calculations, the unknown number is equal to \frac{-45}{7}

  • Let the unknown number be x.

<h3>How to find an unknown number:</h3>

Translate the word problem into an algebraic expression, we have;

Adding 21 to the unknown number:

21 +x

Multiplying the result by 3:

3\times (21+x)

84 more than two-thirds of the unknown number:

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Equating the equations, we have:

3\times (21+x) = \frac{2x}{3} +84\\\\43+3x=\frac{2x}{3} +84

Cross-multiplying, we have:

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Read more on word problems here: brainly.com/question/13170908

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