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Verdich [7]
3 years ago
14

After creating a new email address, Gareth initially receives n emails per year. The number of emails received increases by 7% e

ach year after that. The following expression represents the number of emails received after x years.
n(1+0.07)^x

Which of the following best represents the expression?

A.
the product of the number of emails received initially and the factor of increase raised to a period of x years
B.
the product of the number of emails received initially and one plus the factor of decrease raised to the number of years that the amount of emails Gareth received has increased
C.
the product of the number of emails received initially and one plus the factor of increase raised to the number of years that the amount of emails Gareth received has increased
D.
the product of the number of emails received initially and the factor of decrease raised to a period of x years
Mathematics
1 answer:
RSB [31]3 years ago
4 0

n is the initial amount

0.07 is the factor of increase

x is the number of years that the emails increased

answer: C

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25 is the slop of the math problem


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Find the value of each variables
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<em>X=11</em>

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8 0
3 years ago
There are 25 pens in a container on your desk. Among them, 20 will write well but 5 have defective ink cartridges. You will sele
n200080 [17]

Answer:

3.33% probability that both pens are defective.

Step-by-step explanation:

The pens are chosen without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

2 defective, so x = 2.

25 pens, so N = 25.

Two pens will be selected, so n = 2.

5 are defective, so k = 5.

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,25,2,5) = \frac{C_{5,2}*C_{20,0}}{C_{25,2}} = 0.0333

3.33% probability that both pens are defective.

5 0
4 years ago
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