Answer:
-2/3
Step-by-step explanation:
Log125(1/25)=x
Raise each side to the base of 125
125^Log125(1/25)=125^x
1/25 = 125^x
Rewrite 25 as a power of 5 and 125 as a power of 5
1 / 5^2 = 5^3^x
The if power is in the denominator, we can bring it to the numerator by making it negative
5^-2 = 5^3^x
We know that a^b^c = a^(b*c)
5^-2 = 5^(3*x)
Since the bases are the same, the exponents are the same
-2 = 3x
Divide by 3
-2/3 = 3x/3
-2/3 =x
Use elimination.
-x = -6
X = 6
-4 (6) + 4y = 12
Y = 9
(X,y)
(6,9) is the solution
Step-by-step explanation:
4x + 8y = 40
4x + (8×0.8) = 40
4x + 6.4 = 40
4x = 33.6
4x÷4 = 33.6 ÷ 4
x = 8.4
30%*470=141 (So the number of students in 8 grade is 141)
15,17,19
Suppose the three odd integers are #n#, #n+2# and #n+4#
Their sum is:
#n + (n+2) + (n+4) = 3n+6#
#13# more than twice the largest of the three is:
#2(n+4)+13 = 2n+21#
From what we are told these two are equal:
#3n+6 = 2n+21#
Subtract #2n+6# from both sides to get:
#n = 15#
So the three integers are:
#15, 17, 19#
