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3 years ago

For each sentence, drag a word that will make the statement true.

Mathematics

1 answer:

olchik [2.2K]3 years ago

4 0

Answer:

Equilateral triangles are always acute triangles.

Scalene triangles are sometimes acute triangles.

Right triangles are never acute triangles.

Obtuse triangles are sometimes isosceles triangles.

Step-by-step explanation:

Equilateral triangles are always acute because each angle is 60⁰.

Scalene triangles have sides that are different lengths. They can be right, obtuse, or acute.

A right triangle is never acute because it has a 90⁰ angle. Acute means all angles are less than 90⁰.

An obtuse triangle can be either scalene or isosceles. It always has one angle greater than 90⁰ (obtuse).

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Estimate 43% of 117. (2 points) Show your work to

finlep [7]

Answer:

Let's say 50

Step-by-step explanation:

40% of 100 is 40

50% of 117 is about 59

so number should be a somewhere in between.

8 0

2 years ago

11c - 2d = -2 c + 8d = 8 using the substitution method

Darya [45]

A) 11c - 2d = -2
B) c + 8d = 8
B) c = 8 - 8d then substitute this into A)

A) 88 -88d - 2d = -2
A) 90 = 90d
d = 1
c = 0

4 0

3 years ago

Find the perimeter and area of length 3cm and width 5 cm

Anni [7]

L = 5 and w = 3

Perimeter = 2(l + w)
P = 2(5 + 3)
P = 2(8)
P = 16 cm

Area = l*w
Area = 5*3
Area = 15 cm^2

4 0

3 years ago

What is the equation of the graph below?On a coordinate plane, a curve crosses the y-axis at (0, negative 1). It has a minimum o

zzz [600]

ANSWER:

4th option: y = cosine (x + pi)

STEP-BY-STEP EXPLANATION:

For the function y = cosine (x), when x = 0, y = 1 and when x = , y = -1. The graph shows the opposite, when x = 0, y = -1 and when x = , y = 1, so we must add the same amount x = , for y to be positive 1.

So the equation of the graph would be:

$y=\cos(x+)$

The correct answer is then the 4th option y = cosine (x + pi)

3 0

1 year ago

What is the difference?

Whitepunk [10]

Answer:

$\frac{x^2+3x -12}{(x-5) (x +3)(x+7)}$

Step-by-step explanation:

Given

$\frac{x}{x^2-2x-15} - \frac{4}{x^2+2x-35}$

Required

Calculate the difference

We start by factorizing the denominator of both fractions

$\frac{x}{x^2-2x-15} - \frac{4}{x^2+2x-35}$

$\frac{x}{x^2+3x - 5x -15} - \frac{4}{x^2+7x - 5x-35}$

$\frac{x}{x(x+3) - 5(x +3)} - \frac{4}{x(x+7) - 5(x+7)}$

$\frac{x}{(x-5) (x +3)} - \frac{4}{(x-5)(x+7)}$

Take LCM

$\frac{x(x+7) - 4(x +3)}{(x-5) (x +3)(x+7)}$

Open Brackets

$\frac{x^2+7x - 4x -12}{(x-5) (x +3)(x+7)}$

$\frac{x^2+3x -12}{(x-5) (x +3)(x+7)}$

This can't be simplified any further;

4 0

3 years ago