Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
Answer:
x
Step-by-step explanation:
7x+18−6(x+1)−12
start out with distributive property
7x+18+(-6x)+(-6)+(-12)
then add the common things together
x+0
answer is just x, or infine answers, you could put in anything for x
Answer:
What is the question
Step-by-step explanation:
Answer:
pqr²+pr-rp²+rq²
Step-by-step explanation:
pq(r²+1)-r(p²+q²)
pqr²+pr-rp²+rq²
121 rounded to the nearest 100 is 100 because 121 is closer to 100 than 200.
252 rounded to the nearest hundred is 300 because 252 is closer to 300 than 100.