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harkovskaia [24]
3 years ago
14

Multiply and simplify: –5gh4 • (–2g3h5)

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
8 0
A. 10g4h9

-5gh4(-2g3h5)
(-5 x -2)= 10
(g x g3)=g4
(h4 x h5)= h9
 = 10g4h9
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Evaluate x1 - x-1 + x0 for x = 2.
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Hi! For this problem, you must replace the letter “X” with the number 2. Your equation will then be (2*1)- (2-1)+ (2*0). This will then simplify to: 2 - 1 + 0. Therefore, your final answer will be:

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The sequence an= -(3)" - 1 is graphed below:
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The given sequence is:

a(2)=1

a(3)=3

a(4)=9

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Average rate of change = 

So the average rate of change for the given function from n = 3 to n = 4 is 6

Step-by-step explanation:

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3 years ago
If the yellow image was reflected across the y-axis, what would the ordered pair be for point B?
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3 years ago
Read 2 more answers
A) Write the exponential equation to represent a house purchased for
dsp73

Answer:

= A(t) = 120000(1.06)^t   t = 1 year

We just add ^12 to equal 1/12 months.

Then use the notation below.

Step-by-step explanation:

We simply want to write an equivalent form of the same equation that will allow for the time period to be calculated in years.

For one year, t = 1, we want it to grow 6% = 1.06

Yearly Rate of Growth annual equation: = 7200

P(i) 7200/ 120000 x 100% = 6% per year growth rate

the yearly growth factor is 1 + appreciation rate = 1+i =1+0.06= 1.06

So time in years can be added to t

= A(t) = 120000(1.06)^t   t = 1 year

The yearly growth factor = 1.06

To equate monthly we add the exponent  t*12*1/12 before  120000(1.06)^t

then add 1/12 to replace ^t = monthly, or just keep the t= time

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4 0
3 years ago
Students who party before an exam are twice as likely to fail as those who don't party (and presumably study). If 20% of the stu
True [87]

Answer:

The fraction of the students who failed to went partying = \frac{1}{10}

Step-by-step explanation:

Let total number of students = 100

No. of students partied are twice the no. of students who not partied.

⇒ No. of students partied = 2 × the no. of students who are not partied

No. of students partied before the exam = 20 % of total students

⇒ No. of students partied before the exam = \frac{20}{100} × 100

⇒ No. of students partied before the exam =  20

No. of students who not partied before the exam = \frac{20}{2} = 10

Thus the fraction of the students who failed to went partying = \frac{10}{100} = \frac{1}{10}

8 0
3 years ago
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