Answer:
a. 6
b. 9
Step-by-step explanation:
a. The product modulo 7 can be found from the product of the individual numbers modulo 7:
(88·95·36·702) mod 7 = (88 mod 7)·(95 mod 7)·(36 mod 7)·(703 mod 7) mod 7
= (4·4·1·3) mod 7 = 48 mod 7 = 6
__
b. Powers of 4 mod 11 repeat with period 5:
4 mod 11 = 4
4^2 mod 11 = 5
4^3 mod 11 = 9
4^4 mod 11 = 3
4^5 mod 11 = 1
So, 4^83 mod 11 = 4^3 mod 11 = 9
Answer:4
Step-by-step explanation:
Use the foil method
FIRST
OUTER
INNER
LAST
9x by 5x
9x by -7
-12 by 5x
-7 by -12
Then add and subtract like terms to get the answer.
-1/3
3
-7
Is
Two have the product of -1
12*6= 72*2= 144
12*9= 108*2= 216
6*9= 54*2= 108
144+216+108= 468 m2
Hope this helps
