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3 years ago

Aaron and his friends went trick or

Mathematics

2 answers:

Masteriza [31]3 years ago

7 0

Answer:

4.472 lbs

Step-by-step explanation:

this is a division problem.

"all the candy" is what they are dividing, and "all the candy" weighed 22.36 lbs.

"5" is the number that they are dividing by, because they are dividing the candy among "5" different people.

so you will set up your problem like this:

22.36 lbs÷5=?

the easiest way to solve this would be to put it in a calculator, so that you would get:

4.472 lbs

which is the answer.

sergeinik [125]3 years ago

6 0

Answer:

4.472

Step-by-step explanation:

So we just have to divide

22.36 / 5 = 4.472

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You are planning to email to two lists. the first list has 1,200 names. the second list has 900 names. there are 150 names that

Snezhnost [94]

Answer: There are 1800 unique names from both the lists.

Explanation:

Since we have given that

there are two lists :

In First list, number of names = 1200

In Second list, number of names = 900

According to question , we have also given that

there are 150 names that appear on both lists,

So,

Number of unique names in the first list is given by

$1200-150=1050$

Number of unique names in the second list is given by

$900-150=750$

Therefore, total number of unique names is given by

$1050+750=1800$

Hence, there are 1800 unique names from both the lists.

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3 years ago

Read 2 more answers

Suppose a couple planned to have three children. Let X be the number of girls the couple has.

sesenic [268]

Answer:

a) {GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) {0,1,2,3}

$P(X=2) = \dfrac{3}{8}$

$P(\text{3 boys}) = \dfrac{1}{8}$

Step-by-step explanation:

We are given the following in the question:

Suppose a couple planned to have three children. Let X be the number of girls the couple has.

a) possible arrangements of girls and boys

Sample space:

{GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) sample space for X

X is the number of girls couple has. Thus, X can take the values 0, 1, 2 and 3 that is 0 girls, 1 girl, 2 girls and three girls from three children.

Sample space: {0,1,2,3}

c) probability that X=2

P(X=2)

That is we have to compute the probability that couple has exactly two girls.

$\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

Favorable outcome: {GGB, GBG, BGG}

$P(X=2) =\dfrac{3}{8}$

d) probability that the couple have three boys.

Favorable outcome: {BBB}

$P(BBB) = \dfrac{1}{8}$

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3 years ago

Question #4 i think my answer is wrong . thoughs anyone ?

9966 [12]

Answer:

2nd option is the correct one

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2 years ago

Read 2 more answers

What are the two solutions of 2x^2 = -X^2 - 5x - 1?

Sidana [21]

Answer:

Step-by-step explanation:

Let's solve 2x^2 = -X^2 - 5x - 1. Consolidate all terms on the left side and write 0 on the right side:

3x^2 + 5x + 1 = 0. This is a quadratic equation. Let's solve it for x using the quadratic formula:

a = 3, b = 5, c = 1, and so the discriminant is b^2 - 4ac = 5^2 - 4(3)(1) = 13. Because the discriminant is positive, we know that there are two distinct, real roots; the graphs of y = 2x^2 and y = x^2 - 5x - 1 intersect in two places whose x-coordinates are the real roots mentioned above.

Answer A is not correct as stated, but would be correct if we were to replace "the y-coordinates" with "the x-coordinates."

Answer C would be correct if and only if we write y = x^2 - 5x - 1.

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3 years ago

Anna has 10 to the 2nd power quarters. Jazmin has 10 to the second power dimes Who has more money, Anna or Jasmine? How much mor

Hoochie [10]

Anna has 100 quarters and jazmin has 100 dimes 100 dimes are equal to 10.00 and 100 quarters are equal to 25.00 Anna has more

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2 years ago