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4 years ago

How do I do this I really don't understand anything here

Mathematics

1 answer:

Lera25 [3.4K]4 years ago

8 0

The red arrows show that the lines are parallel, but using the stuff given you can make an equation.
its hard to explain without drawing but starting from the 60 if you can make a Z you will get alternate angles and that mean that the given equation MUST be equal to 60. So,

8x-4=60

8x=60+4

8x=64

x=64/8

x=8 (is your answer)

hope you understand

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Your friend is wrapping 1 meter of twine around a spool with a 2-centimeter diameter. The spool is thin and accommodates only on

Kazeer [188]

Answer:

a) 6 complete times

b) 19.3%

Step-by-step explanation:

In every turn, the diameter of the twine increases 1 cm.

After the first turn, there is a total wrapped of 3.14*2=6.3 cm.

After the second turn, we have wrapped 6.3+3.14*(2+1)=15.7 cm.

If we continue with these algorithm, we have that after the 6th turn we have 84.8 cm wrapped. This is the last complete turn.

T = 0 D = 2 cm. Wrapped = 6.3 cm. Total wrapped = 6.3 cm.

T = 1 D = 3 cm. Wrapped = 9.4 cm. Total wrapped = 15.7 cm.

T = 2 D = 4 cm. Wrapped = 12.6 cm. Total wrapped = 28.3 cm.

T = 3 D = 5 cm. Wrapped = 15.7 cm. Total wrapped = 44 cm.

T = 4 D = 6 cm. Wrapped = 18.8 cm. Total wrapped = 62.8 cm.

T = 5 D = 7 cm. Wrapped = 22.0 cm. Total wrapped = 84.8 cm.

T = 6 D = 8 cm. Wrapped = 25.1 cm. Total wrapped = 110 cm.

There are left (100-84.8) = 15.2 cm to wrap around the twine, which has a 25.1 cm diameter by now.

The perimeter of the twine is 3.14*25.1=78.8 cm.

The percentage of a complete circle that the last wrapping of the twine will make is:

P = 15.2/78.8 = 0.193 = 19.3%

4 0

3 years ago

Having trouble with add or subtracting the given polynomials

Bumek [7]

(2b^2+7b^2+b)+(2b^2-4b-12)

(9b^2+b)+(2b^2-4b-12)

9b^2+b+2b^2-4b-12

11b^2+b-4b-12

11b^2-3b-12

(7g^3+4g-1)+(2g^2-6g+2)

7g^3+4g-1+2g^2-6g+2

7g^3-2g-1+2g^2+2

7g^3-2g+1+2g^2

7g^3+2g^2-2g+1

Hope this helps!

3 0

3 years ago

Read 2 more answers

Mr. Thompson's sixth-grade class is competing in the school field day. There are 16 boys and 12 girls in his class. He divided t

slamgirl [31]

There are 3 girls on each team and 4 boys on each team.

4 0

4 years ago

An experiment consist of rolling 3 fair dice (1 red die, a blue die, and a white die) and recording the number rolled on each di

Setler79 [48]

In 1, there are 6 outcomes for each die, so for three dice, the total combination is 6 x 6 x 6 = 216 outcomes. Hence, the probability of any individual outcome is 1/216 

The outcomes that will add up to 6 are
1+1+4 
1+4+1 
4+1+1 
1+2+3 
1+3+2 
2+1+3 
2+3+1 
3+1+2 
3+2+1 
2+2+2 

Hence the probability is 10/216 

In 3, the minimum sum of the three dice is 3. so we start with this
P(n = 3) 
1+1+1 ; 1/216 

P(n = 4) 
1+1+2 
1+2+1 
2+1+1 ; 3/216 

P(n = 5) 
1+1+3 
1+3+1 
3+1+1 
1+2+2 
2+1+2 
2+2+1; 6/216

The sum in 3 is 10/216 or 5/108

3 0

4 years ago

Which points are coplanar

Minchanka [31]

J I think it should be

6 0

3 years ago