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2 years ago

If the gross domestic product is currently 12,443.9 billion dollars and grows by 5 percent, how much will it be next year?

Mathematics

1 answer:

olganol [36]2 years ago

7 0

Answer:

12,448.9

Step-by-step explanation:

i'm sorry if this is wrong

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-3.25 (5 continues forever) ○ -3.2 (2 continues forever) Greater than or less than

vazorg [7]

Answer:

Less than. <

Step-by-step explanation:

8 0

2 years ago

The table shows a linear function.

sergejj [24]

Answer:

$\large\boxed{y=\dfrac{5}{3}x+9}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept → (0, b)

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

From the table we have an y-intercept (0, 9) → b = 9.

Take other point from the table (-6, -1).

Calculate the slope:

$m=\dfrac{-1-9}{-6-0}=\dfrac{-10}{-6}=\dfrac{5}{3}$

Finally:

$y=\dfrac{5}{3}x+9$

7 0

3 years ago

Solve the given equation. State the number and type of roots. x² + 3x- 4

sesenic [268]

Answer:

x=1, x=-4

Two distinct real roots

Step-by-step explanation:

x² + 3x- 4 = (x - 1)(x + 4)

x=1, x=-4

Two distinct real roots

4 0

2 years ago

Read 2 more answers

Find X : 10/x +2/x = 12.x =

stich3 [128]

Answer: I believe it’s 1,-1. not 100% but pretty positive it is! hope this helps!

5 0

2 years ago

Find the standard deviation of 21, 31, 26, 24, 28, 26

Vesnalui [34]

Given the dataset

$x = \{21,\ 31,\ 26,\ 24,\ 28,\ 26\}$

We start by computing the average:

$\overline{x} = \dfrac{21+31+26+24+28+26}{6}=\dfrac{156}{6}=26$

We compute the difference bewteen each element and the average:

$x-\overline{x} = \{-6,\ 5,\ 0,\ -2,\ 2,\ 0\}$

We square those differences:

$(x-\overline{x})^2 = \{36,\ 25,\ 0,\ 4,\ 4,\ 0\}$

And take the average of those squared differences: we sum them

$\displaystyle \sum_{i=1}^n (x-\overline{x})^2=36+25+4+4+0+0=69$

And we divide by the number of elements:

$\displaystyle \sigma^2=\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n} = \dfrac{69}{6} = 11.5$

Finally, we take the square root of this quantity and we have the standard deviation:

$\displaystyle\sigma = \sqrt{\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n}} = \sqrt{11.5}\approx 3.39$

8 0

3 years ago