Answer:
82.79MPa
Step-by-step explanation:
Minimum yield strength for AISI 1040 cold drawn steel as obtained from literature, Sᵧ = 490 MPa
Given, outer radius, r₀ = 25mm = 0.025m, thickness = 6mm = 0.006m, internal radius, rᵢ = 19mm = 0.019m,
Largest allowable stress = 0.8(-490) = -392 MPa (minus sign because of compressive nature of the stress)
The tangential stress, σₜ = - ((r₀²p₀)/(r₀² - rᵢ²))(1 + (rᵢ²/r²))
But the maximum tangential stress will occur on the internal diameter of the tube, where r = rᵢ
σₜₘₐₓ = -2(r₀²p₀)/(r₀² - rᵢ²)
p₀ = - σₜₘₐₓ(r₀² - rᵢ²)/2(r₀²) = -392(0.025² - 0.019²)/2(0.025²) = 82.79 MPa.
Hope this helps!!
Answer:
1st choice - 1st line- Distributive property applied incorrectly
Step-by-step explanation:
3(a-2) should be 3a-6
Answer:
170.097 grams are in 6 ounces
When we make it into a common denominator, find a common multiple between the denominators. For this instance, it is
3/4=9/12
2/3=8/12
When we see it with a common denominator, 3/4 is bigger than 2/3.
9514 1404 393
Answer:
Step-by-step explanation:
The outside factor multiplies each term in parentheses.
a) 2(b+c) = 2b +2c
b) 5(7h +3m) = 5×7h +5×3m = 35h +15m
c) e(f +g) = ef +eg
