Solve for t T+20.04=14.3
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If the third term of the aritmetic sequence is 126 and sixty fourth term is 3725 then the first term is 8.
Given the third term of the aritmetic sequence is 126 and sixty fourth term is 3725.
We are required to find the first term of the arithmetic sequence.
Arithmetic sequence is a series in which all the terms have equal difference.
Nth term of an AP=a+(n-1)d
=a+(3-1)d
126=a+2d--------1
=a+(64-1)d
3725=a+63d------2
Subtract second equation from first equation.
a+2d-a-63d=126-3725
-61d=-3599
d=59
Put the value of d in 1 to get the value of a.
a+2d=126
a+2*59=126
a+118=126
a=126-118
a=8
=a+(1-1)d
=8+0*59
=8
Hence if the third term of the arithmetic sequence is 126 and sixty fourth term is 3725 then the first term is 8.
Learn more about arithmetic progression at brainly.com/question/6561461
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Alright, lets get started.
Roger can run one mile in 18 minutes.
Jeff can run one mile in 15 minutes.
Suppose in x minutes, they both will catch up.
Roger runs in 18 minutes = 1 mile
So, Roger will run in 1 minute = miles
So, Roger will run in x minutes = miles
Jeff runs in 15 minues = 1 mile
So, Jeff will run in 1 minute = mile
As Jeff gives roger a 1 minute head start, means Jeff will have x-1 minute time to run
So, Jeff will run in (x-1) minute =
As both are cathing up means they both runs same distance, means
Cross Multiplying
x = 6 minutes
So for calculating distance =
Distance = miles
It means it will take 1/3 or 0.33 miles before jeff catches up to roger. : Answer
Hope it will help :)