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BabaBlast [244]
3 years ago
8

Is 8(4x-3) equal to 12x-3

Mathematics
2 answers:
Anastaziya [24]3 years ago
8 0

Answer: No, 8(4x-3) does not equal to 12x-3.

Step-by-step explanation:

To find out whether it is equal or not, you solve first:

8(4x-3)

32x-24

-Result:

32x-24

meriva3 years ago
4 0
No :)

It’s not equal...
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Cual es la ecuacion lineal de estos infinita solucion o no solucion<br>​
coldgirl [10]

Cuando has simplificado la ecuación lo mas posible y las expresiones de los dos lados quedan iguales, hay soluciones infinitas.  Pero, dado que lo has simplificado y son diferentes, no hay solución.

1.) 7x = 12 + 7x - 12

=> 7x = 7x => infinita solución

2.) x - 11 = 11 + x

=> x = 22 + x => no solución

3.) 2(4x - 6) = 8(x + 2)

=> 8x - 12 = 8x + 16 => 8x = 8x + 28 => no solución

4.) 2x - 9 = 2x - 9

=> infinita solución

5.) 8 + 4x = 4x + 10

=> 4x = 4x - 2 => no solución

6 0
2 years ago
Find the measure of CDE
Free_Kalibri [48]

Step-by-step explanation:

Here,

CDE+27+103+50+35=360(BEING THE SUM OF PIE CHART

CDE+215=360

CDE=360-215

CDE=145

(i amnt sure about answer)

5 0
3 years ago
Read 2 more answers
Calculate the product using partial products. 400×45.2= 14.9×100= 200×38.4= 900×20.7= 76.2×200=
DiKsa [7]

Answer:

A. 400*45.2=400*45+400*0.2=18000+80=18080

B. 14.9*100=15*100-0.1*100=1500-1=1490

C. 76.2*200=76*200+0.2*200=15200+4=15204

Step-by-step explanation:

5 0
2 years ago
The quantity demanded x for a product is inversely proportional to the cube of the price p for p &gt; 1. When the price is $10 p
LenaWriter [7]
Q(p) = k/p^3 . . . . . . . . we want to find k
q(10) = k/10^3 = 64
k = 64,000

Revenue = q(p)*p = 64000/p^2
Cost = 150 +2q = 150 +2*64000/p^3

Profit = Revenue -Cost = 64000/p^2(1 -2/p) -150

Differentiating to find the maximum profit, we have
.. dProfit/dp = -2(64000/p^3) +6(64000/p^4) = 0
.. -1 +3/p = 0
.. p = 3

A price of $3 per unit will yield a maximum profit.

7 0
3 years ago
What is the value of x?
leva [86]
Answer
42

Because that angle is 90 degrees so 90-48-42
8 0
2 years ago
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