Answer:
NO
Step-by-step explanation:
Answer:
0
Step-by-step explanation:|-2 - (-1)| =
|-2 + 1| =
| -1 | =
1.
So, we're one unit away from y = -1. If we're one unit ABOVE y=-1, we need to move the point to be one unit BELOW it instead. And if we're one unit BELOW y = -1, we need to move the point to be one unit ABOVE it.
Since the point has a y-coordinate of -2, its BELOW the line y = -1, by 1 unit. Now we change the y-coordinate so its instead ABOVE y = -1, by 1 unit:
(y-coordinate of reflection line) + (number of units above that line) =
-1 + 1 =
0.
Our new y-coordinate is 0, so the point is now at
(7, 0).
A more mechanical, but less intuitive approach is as follows:
Let L = the y-coordinate of the line, and
P = the y-coordinate of the point.
The new y-coordinate is 2L - P.
In this case, L = -1, and P = -2. So we have
2L - P =
2(-1) - (-2) =
-2 -(-2) =
0.
- Vertex Form: y = a(x - h)^2 + k, with (h,k) as the vertex.
So firstly, plug the vertex into the vertex form: 
Next, we first need to solve for a. Plug (0,-6) into the equation to solve for a as such:
<u>Now we know that our equation is y = 3(x - 1)^2 - 9.</u>
Now to solve for the zeros (x-intercepts). Set y to 0 and add 9 to both sides of the equation: 
Next, divide both sides by 3: 
Next, square root both sides: 
Next, add 1 to both sides: 
<u>Your x-intercepts are (-0.73,0) and (2.73,0), or B.</u>
Answer:
175+ braniliest pls
Step-by-step explanation:
175+
Answer:
Step-by-step explanation:
You can isolate the "V" variable by dividing by IT on both sides:
On the left, the IT from the top and bottom cancel, leaving you with just V:
