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DerKrebs [107]
3 years ago
8

7) Solve the following system of equations below algebraically using substitution.

Mathematics
1 answer:
Pani-rosa [81]3 years ago
8 0

Answer:

x = 3.25

y =4.75

Step-by-step explanation:

In order to Solve the following system of equations below algebraically using substitution method we say that;

let;

8x - 4y = 7 ..................... equation 1

x + y = 8.......................... equation 2

from equation2

x + y = 8.......................... equation 2

x = 8 - y.............................. equation 3

substitute for x in equation 1

8x - 4y = 7 ..................... equation 1

8(8-y) - 4y = 7

64-8y-4y=7

64-12y=7

collect the like terms

64-7 = 12y

57= 12y

divide both sides by the coefficient of y which is 12

57/12 = 12y/12

4.75 = y

y =4.75

put y = 4.75 in equation 3

x = 8 - y.............................. equation 3

x = 8 -4.75

x = 3.25

to check if your answer is correct, put the value of x and y in either equation 1 or 2

from equation 2

x + y = 8.......................... equation 2

3.25 + 4.75 =8

8=8.................... proved

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daser333 [38]
<h3>Answer:</h3>

2.25

<h3>Explanation:</h3>

Consider the square ...

... (x+a)² = x² +2ax +a²

The constant term (a²) is the square of half the x-coefficient: a² = (2a/2)².

The x-coefficient in your expression is 3. The square of half that is ...

... (3/2)² = 9/4 = 2.25

Adding 2.25 to both sides gives ...

... x² +3x + 2.25 = 6 + 2.25

... (x +1.5)² = 8.25 . . . . completed square

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