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4 years ago

13

(16 POINTS) (EXPLAIN ANSWER!!)

1 answer:

MAVERICK [17]4 years ago

5 0

Answer:

Step-by-step explanation:

(probability of the first event) x (probability of the second event)

male community college

84/164 93/164

mutiply the two together 1953/6724 or 29%

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An exponential function has a starting value of 13 and a growth rate of 0.78%. Write an equation to model the situation.

Elina [12.6K]

Answer:

The equation that models the situation is $A(t) = 13(1.0078)^t$

Step-by-step explanation:

Exponential equation:

An exponential equation has the following format:

$A(t) = A(0)(1+r)^t$

In which A(0) is the starting value and r is the growth rate, as a decimal.

Starting value of 13 and a growth rate of 0.78%.

This means that $A(0) = 13, r = 0.0078$

Write an equation to model the situation.

$A(t) = A(0)(1+r)^t$

$A(t) = 13(1+0.0078)^t$

$A(t) = 13(1.0078)^t$

The equation that models the situation is $A(t) = 13(1.0078)^t$

4 0

3 years ago

A store manager records the number of people who have been in his store compared to the number of hours the store has been open.

arsen [322]

Answer:

After 7 hours, 175 customers had been in the store.

Step-by-step explanation:

Did the quiz, Trust me.

8 0

4 years ago

Read 2 more answers

HELP ASAP ITS FOR A TEST!

Setler [38]

Answer: reflection on the x access then translation down

Step-by-step explanation:

You can see the reflection because the x axis did not change and then the translation down because it was meant to be (1,-1) but its (1,-2)

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2 years ago

Is 2 feet longer than 30 inches

faust18 [17]

No 2ft is equal to 24 inches < 30 inches

8 0

3 years ago

Read 2 more answers

EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 9z on the curve of intersection of the plane x − y + z =

geniusboy [140]

The Lagrangian,

$L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)$

has critical points where its partial derivatives vanish:

$L_x=1-\lambda-2\mu x=0$

$L_y=2+\lambda-2\mu y=0$

$L_z=9-\lambda=0$

$L_\lambda=x-y+z-1=0$

$L_\mu=x^2+y^2-1=0$

$L_z=0$ tells us $\lambda=9$ , so that

$L_x=0\implies-8-2\mu x=0\implies x=-\dfrac4\mu$

$L_y=0\implies11-2\mu y=0\implies y=\dfrac{11}{2\mu}$

Then with $L_\mu=0$ , we get

$x^2+y^2=\dfrac{16}{\mu^2}+\dfrac{121}{4\mu^2}=1\implies\mu=\pm\dfrac{\sqrt{185}}2$

and $L_\lambda=0$ tells us

$x-y+z=-\dfrac4\mu-\dfrac{11}{2\mu}+z=1\implies z=1+\dfrac{19}{2\mu}$

Then there are two critical points, $\left(\pm\frac8{\sqrt{185}},\mp\frac{11}{\sqrt{185}},1\pm\frac{19}{\sqrt{185}}\right)$ . The critical point with the negative $x$ -coordinates gives the maximum value, $9+\sqrt{185}$ .

8 0

4 years ago