I feel like its either b or c
Answer:
Step-by-step explanation:
Part A
x-intercepts of the graph → x = 0, 6
Maximum value of the graph → f(x) = 120
Part B
Increasing in the interval → 0 ≤ x ≤ 3
Decreasing in the interval → 3 < x ≤ 6
As the price of goods increase in the interval [0, 3], profit increases.
But in the price interval of (3, 6] profit of the company decreases.
Part C
Average rate of change of a function 'f' in the interval of x = a and x = b is given by,
Average rate of change = 
Therefore, average rate of change of the function in the interval x = 1 and x = 3 will be,
Average rate of change = 
= 
= 30
Answer:
B) 40/5
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
Answer:
144 feets
Step-by-step explanation:
Look on s(t) like quadratic function. We need to find maximum of the function using 1st diferetioal:
s(t)=-16t^2+64t+80
s’(t)=-32t+64
S’(t)=0 if t=2
For t>2, s’(t)<0
For t<2, s’(t)>0. So the maximum od function is in the point 2.
S(2)=-16*4+64*2+80=-64+128+80=144