Answer: bruh nobody needs to know this I won’t use this irl
Step-by-step explanation:
From the attached image, we can tell that:
From 1 to 2: There is a shift from left to right along the same plane (x-axis).
From 2 to 3: There is a 90° rotation in the clockwise direction.
From 3 to 4: There is a negative vertical shift. Assuming a y-axis this would be from the top down.
From 4 to 5: There is a 180° rotation in the clockwise direction.
<h3>What is a rotation?</h3>
It is to be noted that a rotation is a sort of transformation that rotates each point in a figure a specific number of degrees around a particular point.
Learn more about rotation in math:
brainly.com/question/26249005
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Full Question:
These five frames (in the attached image_ show shapes of different positions. Describe how the shape moves to get from its position in each frame to the next.
It is 10.7703296143, but estimated it would be about 11. Hope I helped!! :)
Answer:
The other point on the diameter which is also on the circle is; (-3, 2)
Step-by-step explanation:
The center of the circle, also a point where the diameter crosses, is (3, 6)
The diameter touches the circle at point (9, 10)
The displacement is (9 - 3, 10 - 6) = (6, 4)
This means that we move, +6 units along the x-axis and +4 units along the y-axis , from the center of the circle in order to reach point (9, 10)
If we want to reach the other point on the diameter which also on the circle, we move -6 units along the x-axis and -4 units along the y-axis to get;
(3, 6) - (6, 4) = (-3, 2)
This problem can take a while if you cannot observer the answer quickly.
First of all we can see that 32=2*2*2*2*2=2^5
243, if you don't know its actually is 3^5
Now we can see that this turns into...
- 2^5/3^5
since the 5th power doesn't change the sign of the original number, we can put the negative in the ( ), if you don't know what I mean look below
(-3)^2=9 Positive
(-3)^3=-27 Negative since its to the odd power it keeps the sign.
This problem can be simplified to.
(-2/3)^5
And this is the answer :D
If you have any questions just put them in the comments.
