let me tell u I don't know so give me an complete thuought

<u>Step-by-step explanation:</u>
We have ,
,
We know that ![sin\alpha = \frac{Perpendicular}{Hypotenuse} = \frac{Perpendicular}{\sqrt[2]{(Perpendicualr)^{2} + (Base)^{2})} }](https://tex.z-dn.net/?f=sin%5Calpha%20%20%3D%20%5Cfrac%7BPerpendicular%7D%7BHypotenuse%7D%20%3D%20%5Cfrac%7BPerpendicular%7D%7B%5Csqrt%5B2%5D%7B%28Perpendicualr%29%5E%7B2%7D%20%2B%20%28Base%29%5E%7B2%7D%29%7D%20%7D)
Substituting values of P & B , 
Now , 
⇒
×
×2
⇒ 
⇒
⇒
⇒
The x-intercept is (11.43,0) I don’t know how to explain it to you
Answer:
a_n=a_1+(n-1)d
Step-by-step explanation:
sorry for late anwser
Answer:
Step-by-step explanation:
both the length and the width of a square is the same measurement.
so if both measured to "x" then that means one side increase +7.
so one side is x + 7
and the other side decreased -4
so the other side is x - 4
area of square = length x width or just one of the sides to the power of 2
so (x+7) * (x-4) = Area
x^2 + 3x - 21 = area