Answer:
Step-by-step explanation:
The is neither geometric nor arithmetic. The differences have to be the same.
99 - 89.9 = 9.1
89.9 - 78.8 = 11.1
78.8 - 68.7 = 10.1
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The gym teacher has $250 to spend on volleyball equipment. She buys 4 volleyball nets for $28 each. Volleyballs cost $7 each. How many volley balls can she buy
Answer:
she can buy maximum of 19 balls.
Step-by-step explanation:
Let the number of volleyballs be x
we know that
![\text{(The cost of each volleyball net} \times \text{number of volleyball net)}+\text{(the cost of each volleyball} \times \text{number of volleyballs)}\leq \ 250](https://tex.z-dn.net/?f=%5Ctext%7B%28The%20cost%20of%20each%20volleyball%20net%7D%20%5Ctimes%20%5Ctext%7Bnumber%20of%20volleyball%20net%29%7D%2B%5Ctext%7B%28the%20cost%20of%20each%20volleyball%7D%20%5Ctimes%20%5Ctext%7Bnumber%20of%20volleyballs%29%7D%5Cleq%20%5C%20250)
so substituting the values,
![28(4) + 7x \leq 250](https://tex.z-dn.net/?f=28%284%29%20%2B%207x%20%5Cleq%20250)
![112 + 7x \leq 250](https://tex.z-dn.net/?f=112%20%2B%207x%20%5Cleq%20250)
![7x \leq 250 - 112](https://tex.z-dn.net/?f=%207x%20%5Cleq%20250%20-%20112)
![7x \leq 138](https://tex.z-dn.net/?f=%207x%20%5Cleq%20138)
![x \leq \frac{138}{7}](https://tex.z-dn.net/?f=%20x%20%5Cleq%20%5Cfrac%7B138%7D%7B7%7D)
![x \leq 19.7](https://tex.z-dn.net/?f=%20x%20%5Cleq%2019.7)
Answer:
The total cost of the taxi service is the flat free and the total amount that is based on the distance. Let x be this distance. The equation that would best represent the situation is,
1.25 + 0.75x = 14
Solving for x gives the answer of 17. Thus, Henri can afford to travel 17 miles.
Step-by-step explanation:
All the numbers are composite, multiples of 3, and divisible by 2.
The correct answer for the question that is being presented above is this one: "<span>D. 300 yd2."
</span>
We have to get the areas of 5 polygons and add them together to get the surface area.
Area 1 = l * w = 5*8 = 40
Area 2 = l * w = 12 * 8 = 96
Area 3 = l * w = 13 * 8 = 104
Area 4 = bh/2 = 5*12/2 =30
Area 5 = bh/2 = 5*12/2 = 30
Area = Area 1 + Area 2 + Area 3 + Area 4 + Area 5
Area = 40 + 96 + 104 + 30 + 30
Area = 300 yard^2