what is one easy addition equation?
1 + 1 = 2
how did you get this ?
you add 1 and 1 together and you will get your solution.
Answer:
C
Step-by-step explanation:
1 1/4 = 1.25
1 4/5 = 1.8
1.8+1.25=3.05=3 1/20
Answer:
3x^2 -4
Step-by-step explanation:
F(x)=2x^2+3 and g(x)=x^2-7
(f+g)(x) =
We add the two functions together
(f+g)(x) =2x^2+3+x^2-7
I like to line them up vertically
(f+g)(x) =
2x^2 +3
+x^2 -7
------------------
3x^2 -4
Answer:
she has 6 $5 bills and 4 $10 bills I think I'm not sure
Assume 0 < <em>x</em>/2 < <em>π</em>/2. Then
tan²(<em>x</em>/2) + 1 = sec²(<em>x</em>/2) ===> sec(<em>x</em>/2) = √(1 - tan²(<em>x</em>/2))
===> cos(<em>x</em>/2) = 1/√(1 - tan²(<em>x</em>/2))
===> cos(<em>x</em>/2) = 1/√(1 - <em>t</em> ²)
We also know that
sin²(<em>x</em>/2) + cos²(<em>x</em>/2) = 1 ===> sin(<em>x</em>/2) = √(1 - cos²(<em>x</em>/2))
Recall the double angle identities:
cos(<em>x</em>) = 2 cos²(<em>x</em>/2) - 1
sin(<em>x</em>) = 2 sin(<em>x</em>/2) cos(<em>x</em>/2)
Then
cos(<em>x</em>) = 2/(1 - <em>t</em> ²) - 1 = (1 + <em>t</em> ²)/(1 - <em>t</em> ²)
sin(<em>x</em>) = 2 √(1 - 1/(1 - <em>t</em> ²)) / √(1 - <em>t</em> ²) = 2<em>t</em>/(1 - <em>t</em> ²)
