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Damm [24]
3 years ago
13

Select the two binomials that are factors of this trinomial. x^2-3x-28 help please I really bad need it

Mathematics
1 answer:
Fofino [41]3 years ago
8 0

Answer:

(x-7)(x+4)

Step-by-step explanation:

To factor the equation, break it into two binomials which multiply to make the equation. To write these binomials (x+a)(x+b), find factors which multiply to -28 and add to -3 for a and b.

28: 1,2,4,7,14,28

-7+4 = -3

x^2-3x-28 = (x-7)(x+4)

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The ratio of students to adults on a field trip is 8 to 1. Which table correctly shows this ratio for each grade?
elena-14-01-66 [18.8K]

Answer:

The table C correctly shows the ratio 8:1  for each grade

Step-by-step explanation:

Let

x ----> the number of students

y ----> the number of adults

we know that

\frac{x}{y}=\frac{8}{1}

<u><em>Verify each table</em></u>

Table A

grade 6

\frac{96}{88}=\frac{8}{1}

Multiply in cross

96(1)=8(88) ----> is not true

Table B

grade 6

\frac{96}{104}=\frac{8}{1}

Multiply in cross

96(1)=8(104) ----> is not true

Table C

<u><em>grade 6</em></u>

\frac{96}{12}=\frac{8}{1}

Multiply in cross

96(1)=8(12)

96=96 ----> is true

<u><em>grade 7</em></u>

\frac{120}{15}=\frac{8}{1}

Multiply in cross

120(1)=8(15)

120=120 ----> is true

<u><em>grade 8</em></u>

\frac{136}{17}=\frac{8}{1}

Multiply in cross

136(1)=8(17)

136=136 ----> is true

therefore

The table C correctly shows the ratio 8:1  for each grade

Table D

<u><em>grade 6</em></u>

\frac{96}{11}=\frac{8}{1}

Multiply in cross

96(1)=8(11)----> is not true

3 0
3 years ago
Read 2 more answers
A car insurance company has high-risk, medium-risk, and low-risk clients, who have, respectively, probabilities .04, .02, and .0
Paha777 [63]

Answer:

(a) 0.983

(b) 0.353 or 35.3%

(c) 0.604 or 60.4%

Step-by-step explanation:

a) The probability of a random client does not file a claim is equal to the sum of:

1) the probability of a client being high risk and does not file a claim = P(hr)*(1-P(c_hr))

2) the probability of a client being medium risk and does not file a claim = P(mr)*(1-P(c_mr))

and

3) the probability of a client being low risk and does not file a claim = P(lr)*(1-P(c_lr))

P(not claim) = P(hr)*(1-P(c_hr))+P(mr)*(1-P(c_mr))+P(lr)*(1-P(c_lr))

P(not claim) = 0.15*(1-0.04)+0.25*(1-0.02)+0.6*(1-0.01)

P(not claim) = 0.15*0.96+0.25*0.98+0.6*0.99 = 0.983

(b) To know the proportion of claims that come from high risk clients we need to know the total expected claims in every category:

Claims expected by high risk clients = P(c_hr)*P(hr) = 0.04*0.15 = 0.006 claims/client

Claims expected by medium risk clients = P(c_mr)*P(mr) = 0.02*0.25 = 0.005 claims/client

Claims expected by low risk clients = P(c_lr)*P(lr) = 0.01*0.60 = 0.006 claims/client

The proportion of claims done by high risk clients is

Claims by HR clients / Total claims expected = 0.006 / (0.006+0.005+0.006) =  0.006 / 0.017 = 0.3529 or 35,3%

(c)  The probability of being a client of a particular category and who don't file a claim is:

1) High risk: 0.15*(1-0.04) = 0.144

2) Medium risk: 0.25*(1-0.02) =  0.245

3) Low risk: 0.6*(1-0.01) = 0.594

The probability that a random client who didn't file a claim is low- risk can be calculated as:

Probability of being low risk and don't file a claim / Probability of not filing a claim

P(LR&not claim)/P(not claim) = 0.594 / (0.144+0.245+0.594)

P(LR&not claim)/P(not claim) = 0.594 /  0.983 = 0.604 or 60.4%

6 0
3 years ago
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