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masha68 [24]
2 years ago
8

One number exceeds another by 6 .the sum of the numbers is 40. What are the numbers?

Mathematics
2 answers:
tigry1 [53]2 years ago
3 0

Answer:

Let 'another number' be X

Let 'one number' be x+6

X+X+6=72

2X+6=72

2X=66

X=33

'Another number'=33

'One number'=39

Alenkinab [10]2 years ago
3 0
1.)Make into equation: X+X+6=40
2.)Combine like terms: 2x+6=40
3.)Simplify: X=17

X=17
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<u>Hay 2.5 decámetros en 25 metros.</u>

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2 years ago
What is the sum of the integers between the square root of 12 and 40?
satela [25.4K]
1.

the closest perfect squares of 12 are 9 and 16, 

that is 9<12<16

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2.

similarly 

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\sqrt{36}\ \textless \  \sqrt{40}\ \textless \  \sqrt{49}

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3. 

<span>the sum of the integers between the square root of 12 and 40 is the sum of 4, 5 and 6, since 4 is the smallest integer after root 12, and 6 the greatest integer to before root of 40.


Answer: 15</span>
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