Rewrite the equation in Ax+By=C form. Use integers for A, B, and C. y+2=3 (x-6)

Which of the following is a correct solution to the inequality 3x - 12 > 15?

pishuonlain [190]

Solve the inequality just like you would solve an equation
3x - 12 > 15
add 12 to both sides
3x > 27
divide both sides by 3
x > 9
Or read as "the solution to 3x - 12 > 15 is x is greater than 9"

Hope this helps :)

4 0

2 years ago

A bag contains exactly three red marbles, five yellow marbles and two blue marbles. If three marbles are drawn from the bag with

Studentka2010 [4]

Answer:

11/120

Step-by-step explanation:

Red = 3
Yellow = 5
Blue = 2

Possible options would be red or yellow as only two blue marbles.

Probability of 3 red:

3/10*2/9*1/8 = 1/120

Probability of 3 yellow:

5/10*4/9*3/8 = 1/12

Probability of same three is:

1/120 + 1/12 = 11/120

3 0

2 years ago

winnie wrote the following riddle i am a number between 60 and 100 my ones digit is two less than my tens digits im a prime numb

Lina20 [59]

The answer is that 79 IS NOT correct because the riddle says "my ones digit is 2 LESS than my tens digit.." and 79 has 7 in tens and 9 in ones which means the ones digit is 2 MORE than the tens digit.

To solve
x has to be more than 60 and less than 100
the primes between those are 61,67,71,73,79,83, 89, 97
97 is two less in the ones than in the tens so it completes all of the requirements of the riddles therefore, 97 is the answer.

8 0

3 years ago

Read 2 more answers

How many solutions in the equation below 145=10x-8x

iren2701 [21]

Answer:

One

Step-by-step explanation:

145=2x

72.5=x that's one solution.

4 0

2 years ago

A probability experiment is conducted in which the sample space of the experiment is upper s equals startset 4 comma 5 comma 6 c

olchik [2.2K]

The correct question statement is:

A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in $E^{c}$ . Find $P(E^{c})$ .

Solution:

Part 1:

$E^{c}$ means compliment of the set E. A compliment of a set can be obtained by finding the difference of the set from the universal set. The universal set is the set which contains all the possible outcomes of the events which is S in this case.

So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:

$E^{c}=S-E \\ \\ 
E^{c}=(4,5,6,7,8,9,10,11,12,13,14,15)-(7,8,9,10,11,12,13,14,15) \\ \\ 
E^{c}=(4,5,6)$

Thus the set compliment of E will contain the elements {4,5,6}.So

$E^{c}$ = {4,5,6}

Part 2)

$P(E^{c})$ means probability that if we select any number from the Sample Space S, it will belong the set E compliment.

$P(E^{c})$ = (Number of Elements in $E^{c}$ )/Number of elements in S

Number of elements in set S = n(S) = 12
Number of elements in set $E^{c}$ = $n(E^{c})$ =3

So,

$P(E^{c})= \frac{n(E^{c}) }{n(S)} \\ \\ 
P(E^{c})= \frac{3}{12} \\ \\ 
P(E^{c})= \frac{1}{4}$

7 0

2 years ago