Point R is on line segment QS. Given QS= 5x-2, QR= 3x-6, and RS=4x-2, determine the numerical length of RS.

Mathematics

1 answer:

pashok25 [27]3 years ago

8 0

Answer:

The numerical length of RS is 10 units

Step-by-step explanation:

* <em>Lets explain How to solve the problem</em>

- Point R is on line segment QS

- The length of QS is (5x - 2)

- The length of QR is (3x - 6)

- The length of RS is (4x - 2)

- <em>The length of QS is the sum of the lengths of QR and RS</em>

∵ QS = QR + RS

∴ (5x - 2) = (3x - 6) + (4x - 2)

- Simplify the right hand side by adding like terms

∴ 5x - 2 = (3x + 4x) + (-6 + -2)

∴ 5x - 2 = 7x + -8 ⇒ (+)(-) = (-)

∴ 5x - 2 = 7x - 8

- Add 8 for both sides

∴ 5x + 6 = 7x

- Subtract 5x from both sides

∴ 6 = 2x

- Divide both sides by 2

∴ x = 3

- <em>To find the length of RS substitute the value of x in its expression</em>

∵ RS = 4x - 2

∵ x = 3

∴ RS = 4(3) - 2 = 12 - 2 = 10

∴ The numerical length of RS is 10 units

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$\begin{cases}f(x) = 70^{\circ } & \text{ if } 0 \leq x \leq 3 \\f(x) = 50^{\circ} & \text{ if } 3 < x \leq 6 \\ f(x) = 35^{\circ }& \text{ if } 6 < x \leq 12 \end{cases}$

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<h3>How can the step function be written?</h3>

The temperature at it is fermented in the first three days = 70 °F

From day 3 to 6 the temperature = 50 °F

From day 6 to day 12, the temperature at which it is kept in the freezer = 35 °F

The step function is therefore;

$\begin{cases}f(x) = 70^{\circ } & \text{ if } 0 \leq x \leq 3 \\f(x) = 50^{\circ} & \text{ if } 3 < x \leq 6 \\ f(x) = 35^{\circ }& \text{ if } 6 < x \leq 12 \end{cases}$

The graph of the above function created with MS Excel is attached

Learn more about step functions here:

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