If you would like to solve the equation 3 * (3 * x - 1) + 2 * (3 - x) = 0, you can calculate this using the following steps:
3 * (3 * x - 1) + 2 * (3 - x) = 0
3 * 3 * x - 3 * 1 + 2 * 3 - 2 * x = 0
9 * x - 3 + 6 - 2 * x = 0
7 * x + 3 = 0
7 * x = - 3 /7
x = - 3/7
The correct result would be - 3/7.
D if you take 6/25 = 24/100 then change to a decimal and get 0.24
7+8= 15 so the second answer
Yeah i think so because
5-2=3
3+2=3
?
70-20=50
50+20=70
idek
Y=3(x+1)(x-5)
I'm going to ignore 3 for now, but will add it later.
FOIL the (x+1)(x-5)
F = multiply the First numbers x and x
O = multiply the Outside numbers x and -5
I = multiply the Inside number 1 and x
L = multiply the Last numbers 1 and -5
3(x^2 + -5x + 1x + -5)
add -5x and x
3(x^2 + -4x + -5)
multiply the numbers inside the parenthesis by 3
3x^2 + -12x + -15
