Jacob took out a loan for $950 at a 13.2% APR, compounded monthly, to buy

Mathematics

1 answer:

drek231 [11]3 years ago

3 1

Answer:

log( 62.5

62.5 + (950)(0.011))

log(1+0.011)

Step-by-step explanation:

just answered it

You might be interested in

Find the area of this figure. Brainliest to first correct answer. Tysm

larisa [96]

Area of Triangle:
A = 1/2 bh = 1/2 (5)(12) = 30 m^2

Area of semicircle:
A = 1/2 π r^2 = 1/2 π 6^2 = 18π m^2

Area of figure = Area of semicircle + Area of Triangle
Area of figure = 18π + 30 m^2

Answer is C.
18π + 30 m^2

5 0

3 years ago

Read 2 more answers

Find the domain of the rational expression: x-3/2x-8

miss Akunina [59]

Answer:

$\huge\boxed{x\neq4\to x\in\mathbb{R}\backslash\{4\}}$

Step-by-step explanation:

$\dfrac{x-3}{2x-8}$

We know: the denominator must be different than 0.

Therefore

$2x-8\neq0$ add 8 to both sides

$2x-8+8\neq0+8$

$2x\neq8$ divide both sides by 2

$\dfrac{2x}{2}=\dfrac{8}{2}\\\\x\neq4$

6 0

3 years ago

For questions 3 – 5, an airplane is heading south at an airspeed of 540 km/hr, but there is a wind blowing from the northeast at

GuDViN [60]

First, let's calculate the horizontal and vertical components of the wind speed (W) and the airplane speed (A), knowing that south is a bearing of 270° and northeast is a bearing of 45°:

$\begin{gathered} W_x=W\cos45°\\ \\ W_x=50\cdot0.707\\ \\ W_x=35.35\\ \\ \\ \\ W_y=W\sin45°\\ \\ W_y=50\cdot0.707\\ \\ W_y=35.35 \end{gathered}$ $\begin{gathered} A_x=A\cos270°\\ \\ A_x=540\cdot0\\ \\ A_x=0\\ \\ \\ \\ A_y=A\sin270°\\ \\ A_y=540\cdot(-1)\\ \\ A_y=-540 \end{gathered}$

Now, let's add the components of the same direction: