Answer:
the answer is c
Step-by-step explanation:
The radical function is 3√x + 1.
Since the cubic root of zero is zero, 0 would be x.
Add zero and one, which gives you 1. 1 is y.
You get (0,1)
Since this is a positive radical, it would be going to the top right.
So, the domain is x ≥ 0
the range is y ≥ 1
f(x) = 2 
-4x
Step-by-step explanation:
Step 1 :
Given, f(x) = a(x - h)2 + k
Point on the parabola is (3, 6)
Vertex (h,k) = (1,-2)
Step 2:
Substituting the vertex in the equation we have,
f(x) = a(x-1)2 -2
Substituting the point (3,6) in this we have,
6 = a(3-1)2 - 2 => 6 = 4a -2
=> 4a = 8 => a = 2
Step 3 :
Substituting the value for a and the vertex in the given equation we have
f(x) = 2(x-1)2 -2 = 2(x2 - 2x + 1) -2 = 2x2 - 4x
=> f(x) = 2 -4x which is the standard form
It is an acute triangle bc 8 squared + 14 squared is 260 and that is more than 15 squared (225)
Answer:
Step-by-step explanation:
y = 3*x + 4
y = 3*x - 7
Each one of the above equations is the equation for a straight line.
The solution for such a system is the point P ( x₀ , y₀ ) which coordinates belong to both straight lines. According to this, there is only one solution for that system ( only one point of intersection). The intersection of a pair of straight lines either can occur or not depending on the slope of the lines, if they have the same slope they are parallel, then they did not touch each other ever. How can m, be identified in the straight line equation??, just by looking at the coefficient of x.
The two equations have slope 3 they are parallel then there is not a solution ( there is not a common point to both equations)
