Answer:
25 units
Step-by-step explanation:
Applying Pythagoras' Theorem,
(BD)^2= (CD)^2 + (BC)^2
(BC)^2= 65^2 - 60^2
(BC)^2= 625
BC= √625= 25
13 I guess, or 12 i don't rlly know
Answer:84
Step-by-step explanation:
Okay. Are you taking calc? Dv/dt =d/dt(L(t)^3)=d/dt[(sqrt(14)+2t)^3]= 6(Sqrt(14)+2t)^2)=44. We defined t=0 to be time at which length is sqrt(14). Does that work?
Set each equation equal to zero.
y + 5 = 0
Subtract 5 from both sides.
y = 0 - 5
y = - 5
y - 9 = 0
Add 9 to both sides
y = 0 + 9
y = 9
y = - 5, 9
