Answer:
63 i think if its not correct then delete the answer i gave u. hope it helped :)
Step-by-step explanation:
Answer:
(0,10)
Step-by-step explanation:
Im pretty sure bc of subtracting 1 from the -1 in your x vaue and adding 2 to the 8 in you Y value
Answer:
The mean would become greater.
Step-by-step explanation:
With an outlier of 88, and the mean being 6, the average would change so much!
Hope this helped
:)
Answer:
see explanation
Step-by-step explanation:
12
Since the denominators are like, add the numerators leaving the denominator
= ![\frac{x+4+x-1}{x-2}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%2B4%2Bx-1%7D%7Bx-2%7D)
= ![\frac{2x+3}{x-2}](https://tex.z-dn.net/?f=%5Cfrac%7B2x%2B3%7D%7Bx-2%7D)
15
We require the denominators to be like before we can add.
factor x² - 4 as a difference of squares
x² - 4 = (x + 2)(x - 2)
Expressing as
+ ![\frac{2x-12}{(x+2)(x-2)}](https://tex.z-dn.net/?f=%5Cfrac%7B2x-12%7D%7B%28x%2B2%29%28x-2%29%7D)
multiply the numerator/denominator of the first fraction by (x - 2)
=
+ ![\frac{2x-12}{(x+2)(x-2)}](https://tex.z-dn.net/?f=%5Cfrac%7B2x-12%7D%7B%28x%2B2%29%28x-2%29%7D)
Expand and simplify the numerators, leaving the denominator
= ![\frac{x^3-6x^2-2x^2+12x+2x-12}{(x+2)(x-2)}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E3-6x%5E2-2x%5E2%2B12x%2B2x-12%7D%7B%28x%2B2%29%28x-2%29%7D)
= ![\frac{x^3-8x^2+14x-12}{(x+2)(x-2)}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E3-8x%5E2%2B14x-12%7D%7B%28x%2B2%29%28x-2%29%7D)
Answer:
a= 4
b= -1
c= 10
Step-by-step explanation:
First we start by multiplying both sides of 1/2c = 5 by 2.
c = 10
Add b to both sides of the last equation to make it a=b+5
knowing these two things, we can plug them into the first equation like this:
2(b+5) + b + 10 = 17
then you solve for b:
distribute the 2
2b + 10 + b + 10 = 17
combine like terms
3b + 20 = 17
subtract 20 from each side
3b = -3
divide by 3
b = -1
then you can plug that into the last equation again so a - (-1) =5
Subtracting a negative is the same as adding so its a + 1 = 5 or a = 4