All categories

3 years ago

What is cos 45º?...........

Mathematics

1 answer:

Alenkinab [10]3 years ago

5 0

Answer:

$\frac{1}{\sqrt{2} }$

Step-by-step explanation:

Cosine (cos) is adjacent by hypotenuse. $\frac{adjacent}{hypotenuse}$

In any of the 45° angles, 1 is adjacent and √2 is the hypotenuse.

So arrange them to get $\frac{1}{\sqrt{2} }$

You might be interested in

Forty-two divided by seven plus the quantity three divided by six

ikadub [295]

Answer:

i think its 6.5

Step-by-step explanation:

42/7 = 6

3/6 = 0.5

6+0.5=6.5

6 0

3 years ago

What are two expressions that are equivalent to 6(5j + 2 + j)?<br><br><br><br>

ziro4ka [17]

Answer:

1. 30j+12+6j

2. 36j+12

3. 6(6j+2)

Step-by-step explanation:

1. You just multiply so... 6x5j ... 6x2 ... 6xj

2. you multiply and then simplify so first you have 30j+12+6j, so you add like terms so... 30j+6j= 36j and then +12

3. you do what's in the parentheses first so 5j+j=6j so .... 6(6j+2)

5 0

4 years ago

A circle with area 16pi has a sector with a central angle of 8/5pi radians. What is the area of the sector?

lianna [129]

Answer:

The area of the sector is $12.8\pi\ units^2$

Step-by-step explanation:

we know that

The area of a complete circle (16π units^2) subtends a central angle of 2π radians

using proportion

Find out the area of a sector , if the central angle is equal to 8π/5 radians

$\frac{16\pi}{2\pi}=\frac{x}{(8\pi/5)}\\\\x=8(8\pi/5)\\\\x= 12.8\pi\ units^2$

4 0

4 years ago

Read 2 more answers

Simplify 4/(√5+ √2) - 3/(√5- √2)

MakcuM [25]

Step-by-step explanation:

$\frac{4}{ \sqrt{5} + \sqrt{2}} - \frac{3}{ \sqrt{5} - \sqrt{2} } = \\ = \frac{4( \sqrt{5} - \sqrt{2} ) - 3( \sqrt{5} + \sqrt{2} ) }{( \sqrt{5} + \sqrt{2} )\times ( \sqrt{5} - \sqrt{2} )} = \\ = \frac{4 \sqrt{5} - 4 \sqrt{2} - 3 \sqrt{5} - 3 \sqrt{2} }{5 - \sqrt{10} + \sqrt{10} - 2 } = \\ = \frac{ \sqrt{5} - 7 \sqrt{2} }{3}$

8 0

3 years ago

If m ∠ 8 = 65 degrees, what is m ∠ 5 ? (Image in details)

Nitella [24]

65°

It's opposite on a 180° line.

7 0

3 years ago