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3 years ago

If h(x) is the inverse of f(x), what is the value of h(f(x))? OO 0 1 f(x)

Mathematics

2 answers:

kozerog [31]3 years ago

8 0

Answer:

Step-by-step explanation:

h(f(x) = x.

For example the inverse of f(x) = 2x is g(x) = x/2

f((gx)) 2 (x/2)

= 2x / 2

= x.

butalik [34]3 years ago

5 0

<h2>Answer:</h2>

If h(x) is the inverse of f(x), then the value of h(f(x)) is:

<h2>Step-by-step explanation:</h2>

Inverse of a function-

The inverse of a given function is a function which reverses the action of the other function.

Also, the composition of a function and it's inverse no matter in which order they are applied always gives us the identity function.

( Identity function-- Identity function is a function which when applied to some other function always retains that function )

i.e. If h(x) is the inverse of f(x) ; then we have:

$h(f(x))=f(h(x))=x$

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Answer:

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Step-by-step explanation:

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so, this needs to be an expression of the third degree (there must be a term with x³ as the highest power of x).

and that is only possible when multiplying both basic functions. all the other options would keep it at second degree (x²) or render it even to a first degree (linear).

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2 years ago

For the polynomial function ƒ(x) = x4 −25x2, find the zeros. Then determine the multiplicity at each zero and state whether the

AfilCa [17]

<u>ANSWER</u>

The zeros are $x=-5,x=0,x=5$

EXPLANATION

Given;

$f(x)=x^4-25x^2$ .

We can rewrite the function as

$f(x)=x^2(x^2-25)$

$\Rightarrow f(x)=x^2(x^2-5^2)$

$\Rightarrow f(x)=x^2(x-5)(x+5)$

The zeros are found by equating the function to zero.

$\Rightarrow x^2(x-5)(x+5)=0$

$\Rightarrow (x-5)=0$

The multiplicity is 1, since it is odd the graph crosses at this intercept. which is $x=5$

$\Rightarrow (x+5)=0$

The multiplicity is 1, since it is odd the graph crosses at this intercept. which is $x=-5$

$\Rightarrow x^2=0$

This last root has a multiplicity of 2.

That is

$x=0$ repeats two times.

Since the multiplicity is even, the graph touches the x-axis at the point $x=0$ .

See graph.

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3 years ago