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podryga [215]
2 years ago
15

A pencil and an eraser cost 1.10 together. if the pencil costs one dollar more than the eraser how much does the eraser cost

Mathematics
1 answer:
Kazeer [188]2 years ago
8 0

1 pencil + 1 eraser = $1.10


Pencil cost $1 more than the eraser.

⇒ If we take away $1 from the total, both the pencil and the eraser will cost the same.

⇒ $1.10 - $1.00 = $0.10


Divide by 2 to find the cost of the eraser.

⇒$0.10 ÷ 2 = $0.05


Find the cost of the pencil, which is $1 more than the eraser.

⇒ $0.05 + $1 = $1.05


Answer: The eraser costs $0.05



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Evaluate the following expression:<br> 62 − 7(8 + 6 − 32)
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Answer:

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Step-by-step explanation:

<u>Step 1:  Distribute</u>

62 − 7(8 + 6 − 32)

62 + (-7 * 8) + (-7 * 6) + (-7 * -32)

62 + (-56) + (-42) + (224)

<u>Step 2:  Combine the first two numbers</u>

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<u>Step 3:  Combine the next two number</u>

(6 - 42) + 224

-36 + 224

<u>Step 4:  Combine the last two number</u>

-36 + 224

188

Answer:  188

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Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Explain the formula to use

Using the cosine rule which states that:

z^2=x^2+y^2-2xy\cos Z

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\begin{gathered} By\text{ substitution,} \\ z^2=4^2+6^2-2(4)(6)\cos41 \\ z^2=16+36-48cos41 \\ z^2=52-36.22605985 \\ z^2=15.77394015 \\ z=\sqrt{15.77394015} \\ z=3.971641997 \\ z\approx4.0 \end{gathered}

Hence, the indicated length is 4.0

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