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Whitepunk [10]
2 years ago
5

Which of these is a correct step in constructing congruent line segments?

Mathematics
2 answers:
Licemer1 [7]2 years ago
6 0
The answer is D use a compass to create the distance between the endpoints
Fed [463]2 years ago
3 0

Answer:

D. Use a compass to create the distance between the endpoints.

Step-by-step explanation:

I just took the test yesterday.

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How many toys were stuffed animals
Umnica [9.8K]

Answer:

It would be the first one.

Step-by-step explanation:

The way you figure it out is that it said that there was a total of 80 stuffed animals, so model B is out. Then, you change the percent into a decimal by moving the decimal point over to the right 2 times and you get 0.30. Finally, you multiply 80 by 0.30 and you get 24 stuffed animals.

4 0
3 years ago
Read 2 more answers
What is the value of the third quartile of the data set represented by this box plot?
elena55 [62]
Answer: Since you didn't include the picture, I can give you the description so you know how to pick the correct answer.

The third quartile of a data is always shown in a box plot. In the middle of your graph should be a box. The third quartile is the value that goes with the far right edge of the box.
8 0
2 years ago
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30 points! Find the angles formed by two intersecting lines, if the sum of three of the four angles is equal to 270°.
nydimaria [60]
Each angle is 90 degrees because 90 times 3 is 270.
8 0
3 years ago
Splitting Squares (square root)<br><br> Number 34 (picture above)
miskamm [114]

Answer: 3rp\sqrt{5}

<u>Step-by-setp explanation:</u>

  \sqrt{45r^{2}p{2}}

= \sqrt{3*3*5*r*r*p*p}

= 3*r*p\sqrt{5}

= 3rp\sqrt{5}

6 0
3 years ago
A person wishes to mix coffee worth nine dollars per pound with coffee worth three dollars per pound to get 240 pounds of a mixt
Anastasy [175]
\bf \begin{array}{lccclll}&#10;&amount&price&priced\ amount\\&#10;&-----&-----&--------\\&#10;\textit{9 bucks/lb}&x&9&9x\\&#10;\textit{3 bucks/lb}&y&3&3y\\&#10;-----&-----&-----&-------\\&#10;mixture&240&5&1200&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;x+y=240\implies \boxed{y}=240-x\\&#10;9x+3y=1200\\&#10;----------\\&#10;9x+3\left( \boxed{240-x} \right)=1200&#10;\end{cases}

solve for "x".

what about "y"? well, y = 240 - x
4 0
3 years ago
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