you would expect 99 duds in a box of 1430. 1430 divided by 130 is 11. therefore, multiply the amount of duds in the package of 130 times 11.
Hope this helps!!
Solve whats in the parentheses first
5k+25+4<21+6k
5k+29<21+6k
plug in a number in k for both sides
5(1)+29<21+6(1)
5+29<21+6
34<27
5(2)+29<21+6(2)
10+29<21+12
39<33
so 5(k+5)+4 is greater than 21+6k
Answer: 3(5x - 4)
Step-by-step explanation: You first renarange your terms. Then you distribute them. Then you combine the the like terms. Then you find the common factor by factoring by group.
The statement is a conditional statement.
Hello! I believe that 630 would be the most appropriate answer! I hope I helped!