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saul85 [17]
3 years ago
8

Helpppppppppppppppppppppppppppp

Mathematics
2 answers:
elena-s [515]3 years ago
8 0

Given : \sqrt{64}

\implies \sqrt{64} = \sqrt{8\times8} = \sqrt{8^2} = (8^2)^\frac{1}{2} = 8^\frac{2}{2} = 8

Hence : \sqrt{64} = 8

nevsk [136]3 years ago
4 0
1. Write the number in exponential form with a base of 8.

2. Reduce the index of the radical and exponent with 2.

3. Your answer is 8

I hope this helps☺
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Answer:

x = 12

Step-by-step explanation:

Recall: the secant-tangent rule states that when a secant and a tangent meet at an external point of a circle, the product of the secant and the external segment is equal to the square of the tangent segment

(x)(3) = 6² (secant-tangent rule)

3x = 36

Divide both sides by 3

3x/3 = 36/3

x = 12

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Read 2 more answers
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