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4 years ago

Find the volumee..❤️

Mathematics

1 answer:

jeyben [28]4 years ago

6 0

Answer:

640 feet cubed

Step-by-step explanation:

Volume=length x width x height

V=8 x 10 x 8

V=640

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Which ordered pair could not be the coordinates for a clockwise rotation of the point W(-3, 4)?

Eduardwww [97]

Step-by-step explanation:

<em>Look at the picture.</em>

Any pair of choice can be the coordinates of the rotation of the point

W (-3, 4) clockwise.

All points have the same distance from the beginning.

The formula of a distance between the origin and a point (x, y):

$d=\sqrt{x^2+y^2}$

W(-3, 4)

$d=\sqrt{(-3)^2+4^2}=\sqrt{9+16}=\sqrt{25}=5$

(3, -4)

$d=\sqrt{3^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5$

(4, 3)

$d=\sqrt{4^2+3^2}=\sqrt{9+16}=\sqrt{25}=5$

(-4, -3)

$d=\sqrt{(-4)^2+(-3)^2}=\sqrt{9+16}=\sqrt{25}=5$

(-4, 3)

$d=\sqrt{(-4)^2+3^2}=\sqrt{9+16}=\sqrt{25}=5$

3 0

3 years ago

NEED HELP ASAP: Let f(x)=x2−6x+13 . What is the vertex form of f(x)? What is the minimum value of f(x)? Enter your answers i

Svetach [21]

The vertex form of $f(x)=ax^2+bx+c$
$f(x)=a(x-h)^2+k$

where: $h=\dfrac{-b}{2a};\ k=f(h)$

We have: $f(x)=x^2-6x+13\to a=1;\ b=-6;\ c=13$

substitute:
$h=\dfrac{-(-6)}{2\cdot1}=\dfrac{6}{2}=3\\\\k=f(3)=3^2-6\cdot3+13=9-18+13=4$
The vertex form of f(x):
$f(x)=(x-3)^2+4$
The value of minimum is equal k.
Therefore: $y_{min}=4$

5 0

4 years ago

Read 2 more answers

What is the vertex of g(x) = –3x2 + 18x + 2?

Varvara68 [4.7K]

$\bf \textit{vertex of a parabola}\\\\

\begin{array}{lccclll}
g(x) = &-3x^2&+ 18x& + 2\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)$