X+Y=10
XY=-300
Solve for one of the variables
X=10-Y
Plug into the other equation
Y(10-Y)=-300
Now, you have a quadratic...
-y²-10y+300=0
I would multiply everything by -1, so there's no coefficient on y²
y²+10y-300=0
And solve...
-10±√(100-4(-300))
----------------------------
2
Y=-5±5√(13)
Plug back onto original equation...
X+(-5±5√(13))=10
X±5√(13)=15
X=15±5√(13)
Note: There are 2 sets of answers, keep the negatives with the negatives, and the positives with the positives when dealing with the ±.
I hope this helps you
10x^13.y^10
Answer:
I believe the answer would be 1,706.1
Step-by-step explanation:
Since the problem is a fraction, it would be easier to covert it to a decimal. This is made simple since the fraction is out of ten. Now, the number should look like this: 36.3
Now let's do long division.
Now we have answer of 1706.1
We have one more step. Since there is one number behind the decimal point in 36.3, we have to put one number behind the decimal point in our answer.
As you can see in the last picture, we have 1,706.1.
I hope you understand after I have explained. If you have any other troubles, tell me.
The instantaneous rate of change is simply equivalent to
the first derivative of the equation or function. We are given the equation of
Surface Area (A) with respect to side (x):
A = 6 x^2
Taking the first derivative of the equation:
dA = 12 x dx
dA / dx = 12 x
Now the term dA / dx is the instantaneous rate of change
in the surface area with respect to the side length. To get the rate of change
when the side x = a, simply plug this in into the equation:
rate of change = dA / dx = 12 x
so when x = a:
<span>rate of change = 12 a</span>
