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Nookie1986 [14]
3 years ago
8

17. What's the difference between 1,968 and 3,000? Check your answer using inverse operations.

Mathematics
1 answer:
Georgia [21]3 years ago
6 0
The difference between 1,968 and 3,000 is 1,038. You can check the answer using inverse operations by adding 1,038 and 1,968. If it gives 3,000 then the answer is right. 3, 000 - 1,968 = 1,038.

1,038 + 1,968 = 3,000
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13. Danny is in science class and is given a square block of metal with
jenyasd209 [6]

Answer: 336g.

Step-by-step explanation:

the formula for density is mass divided by volume (m/v). In this problem, you mus first find the volume of the square block. The formula for volume is length multiplied by width multiplied by height (LxWxH). To solve for volume you plug in the values to the equation: 6x4x2 = 48.

Now, you have the volume, and you have the density. Now you need to solve for mass. Plug in the values you have into the density equation (d=m/v):

7=m/48

to isolate M, multiply each side by 48. this leaves you with 7x48 = m. now all thats left is to solve. 7x48 = 336g. You can double check by plugging the values back into the equation. 336/48 = 7.

5 0
3 years ago
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Nezavi [6.7K]

Step-by-step explanation:

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7 0
3 years ago
Write as a fraction in simplest form.
seropon [69]

Answer:

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7 0
3 years ago
Two cables support a 800​-lb ​weight, as shown. Find the tension in each cable.
jeka94

Answer:

  • 892 lb (right)
  • 653 lb (left)

Step-by-step explanation:

The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...

  Rcos(45°) +Lcos(75°) = 800

  Rsin(45°) -Lsin(75°) = 0

Solving these equations by Cramer's Rule, we get ...

  R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))

     = 800sin(75°)/sin(120°) ≈ 892 . . . pounds

  L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds

The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.

_____

This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...

  (right, left) = w/sin(α+β)×(sin(β), sin(α))

5 0
3 years ago
The length of a rectangle is 5 in. more than 3 times its width. The quadratic function f(x) = x(3x + 5) represents the area of t
saveliy_v [14]
F(x)=x(3x+5)
or
f(x)=3x²+5x
Here the domain in general is: -∞<x<∞
But the length of the rectangle cannot be negative, therefore the domain is all real numbers greater than zero.

Option D is correct.


5 0
3 years ago
Read 2 more answers
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