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3 years ago

How do I graph y=1/2x+7

Mathematics

2 answers:

xz_007 [3.2K]3 years ago

6 0

Answer:

go to 7 on the y Axis, point it, the go up 1 and over 2, then point that.

Klio2033 [76]3 years ago

4 0

if you look on the graph i gave you you have the answer

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30.54

leonid [27]

<h3>Answer: Choice 2) sin(B) = cos(90-B)</h3>

Explanation:

The rule is that

sin(A) = cos(B)

if and only if A+B = 90.

Solving for A gets A = 90-B

So we end up with

sin(90-B) = cos(B)

which is the same as

cos(B) = sin(90-B)

5 0

3 years ago

Help now plz asphejdjdb

Cloud [144]

Answer:

l:4

w: 3

l:4

w:1

Step-by-step explanation:

Hope this helps

8 0

3 years ago

Solve the system by the elimination method. -2x + y + 6 = 0 2x + y - 8 = 0 When you eliminate x, what is the resulting equation?

Natali5045456 [20]

For this case we have the following system of two equations with two unknowns:

$-2x + y + 6 = 0\\2x + y-8 = 0$

Adding both equations we have to eliminate the variable "x":

$y + y + 6-8 = 0$

Adding common terms, keeping in mind that different signs are subtracted and the sign of the major is placed:

$2y-2 = 0\\2y = 2$

Answer:

$2y = 2$

Option A

5 0

3 years ago

What is the product?<br><br> (6 r minus 1)(negative 8 r minus 3)

just olya [345]

Answer:

The required product is $-48r^2-10r+3$

Step-by-step explanation:

Consider the provided expression.

$(6r-1)(-8r-3)$

Open the parentheses.

$6r\left(-8r\right)+6r\left(-3\right)+\left(-1\right)\left(-8r\right)+\left(-1\right)\left(-3\right)$

$-6\cdot \:8rr-6\cdot \:3r+1\cdot \:8r+1\cdot \:3$

$-48r^2-18r+8r+3$

Add the like terms.

$-48r^2-10r+3$

Hence, the required product is $-48r^2-10r+3$

3 0

3 years ago

Read 2 more answers

Help!! limited time!!

Zina [86]

Hope this helps
1.) 2(8×-1)+ 2(2×+4)
2. 16x-2+ 4x+8
3. 20x+6

7 0

3 years ago