Solve 4x+2y=-6 for y
2 answers:
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Alright, lets get started.
Justin is asked to solve the linear equations using elimination method.
By using elimination method means we have to multiply some numbers in our given equations in such a way that the co-efficient of x or y become same in both equations so that we could add or subtract them to cancel one of the term either x or y.
So, given equations are :
See we have 5x in first equation and -20x in second equation.
So, we try to change 5x into 20 x by multiplying it with 4, both of the equations will have 20 x in common
Lets multiply 4 in first equation
Now both equations could be added and 20 x will be cancelled out and we could easily find the value of y then solve for x.
So, Justin should try to change 5 so that it will be cancels, so option B : Answer
Hope it will help :)
This problem can be completed in 2 ways. Both are acceptable.
Option 1:
This is an isosceles trapezoid that can be divided into a rectangle and two congruent triangles.
The area of the rectangle is the base times the height.
The area of one of the triangles is half the base times the height.
The other triangle must have that area too.
The area is 56 square centimeters.
Option 2:
We can use the area formula for the trapezoid.
Where
is the length of the shorter base
and
is the length of the longer base
and
is the height.
The length of the shorter base is 9.
The length of the longer base is 9+5+5, or 19.
The height is 4.
Same answer. The area is 56 square centimeters.
Both options are two acceptable ways the problem can be tackled.
Option 1:
This is an isosceles trapezoid that can be divided into a rectangle and two congruent triangles.
The area of the rectangle is the base times the height.
The area of one of the triangles is half the base times the height.
The other triangle must have that area too.
The area is 56 square centimeters.
Option 2:
We can use the area formula for the trapezoid.
Where
and
and
The length of the shorter base is 9.
The length of the longer base is 9+5+5, or 19.
The height is 4.
Same answer. The area is 56 square centimeters.
Both options are two acceptable ways the problem can be tackled.