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nlexa [21]
3 years ago
14

What is the largest possible value of x given that

^3 = 5x" alt="x^3 = 5x" align="absmiddle" class="latex-formula">? Express your answer in simplest radical form.
Mathematics
1 answer:
sergey [27]3 years ago
8 0

x^3 = 5x

Subtract 5x from both sides:

x^3 - 5x = 0

Factor X out of x^3:

x(x^2-5x) = 0

Set X to 0 and solve for x:

x = 0

Set (X^2-5) to equal 0 and solve for x:

x^2 - 5 = 0

Add 5 to both sides:

x^2 = 5

Take the square root of both sides:

x = √5, -√5

The three solutions of x are 0, √5, -√5

In order from smallest to largest = -√5, 0, √5

The largest possible value is √5

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-3=x/-9 please tell me how to solve this I’m way behind and trying to learn thank you :)
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To make this easier, I'll put it in normal numbers

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3 years ago
How to make this a simultaneous equation?
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