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podryga [215]
3 years ago
12

A game at the school carnival involves drawing colored marbles out of a bag for a prize. If you draw a red or blue marble, you w

in. If you draw a green or yellow marble, you lose. After each marble is drawn, it is put back in the bag.
You watch several people play with the following results:

G G G B Y G Y G G B G R B Y G R G B Y Y

Based on your observations, what is the probability that you will win?
A
0.20
B
0.30
C
0.45
D
0.70
Mathematics
1 answer:
mina [271]3 years ago
4 0
All up there are 20 marbles and only 6 of those are chances of winning so we make it into a fraction 6/20 then times 20 by five to get to 100 (what ever we do to the bottom we do to the top) times 6 by five giving you a fraction of 30/100 then divide 30 by 100 giving you 0.30 ANSWER EQUALS = 0.30
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A toothpaste company mailed a survey to 360 households. In the first two weeks, the toothpaste company received 45% of the surve
trasher [3.6K]

Answer:

A)162

Step-by-step explanation:

5 0
2 years ago
What is the answer of this question? ​
TEA [102]

9514 1404 393

Answer:

  970

Step-by-step explanation:

It turns out that the radical terms cancel, so the result is an integer. You can find the integer value using your calculator. It is ...

  (5 +2√6)³ +1/(5 +2√6)³ = 970

_____

The cube of 'a' is ...

  (5+2√6)³ = 5³ +3·5²·2√6 +3·5·(2√6)² +(2√6)³

  = 125 +3·50√6 +3·120 +48√6

  a³ = 485 +198√6

The reciprocal of this is ...

  b³ = 1/a³ = 1/(485 +198√6) = (485 -198√6)/(485² -6·198²) = (485 -198√6)/1

  b³ = 485 -198√6

Then the sum is ...

  a³ +b³ = (485 +198√6) +(485 -198√6) = 970

6 0
3 years ago
3. Scout is conducting a research project on traffic patterns
ddd [48]

Answer:

7:45

Step-by-step explanation:

Since they both turn red at differnt times, you have to find a multiple to find the time they will be both on

Main St: 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98, 105

Elm St. 15, 30, 45, 60, 75, 90, 105

They will both turn on 105 minutes or 1 hour and 45 minutes from 6

6 + 1 hr 45 min = 7:45

8 0
3 years ago
Solve the equation. Then check your solution.
ra1l [238]

Answer:

4

Step-by-step explanation:

7 0
3 years ago
In a random sample of 80 teenagers, the average number of texts handled in a day is 50. The 96% confidence interval for the mean
Nastasia [14]

Answer:

a) \bar X =\frac{46+54}{2}=50

And the margin of error is given by:

ME= \frac{54-46}{2}= 4

The confidence level is 0.96 and the significance level is \alpha=1-0.96=0.04 and the value of \alpha/2 =0.02 and the margin of error is given by:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

We can calculate the critical value and we got:

z_{\alpha/2} = 2.05

And if we solve for the deviation like this:

\sigma = ME * \frac{\sqrt{n}}{z_{\alpha/2}}

And replacing we got:

\sigma =4 *\frac{\sqrt{80}}{2.05} =17.45

b) ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}=2.05 *\frac{17.45}{\sqrt{160}}=2.828

And as we can see that the margin of error would be lower than the original value of 4, the margin of error would be reduced by a factor \sqrt{2}

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n=80 represent the sample size  

Solution to the problem

Part a

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

For this case we can calculate the mean like this:

\bar X =\frac{46+54}{2}=50

And the margin of error is given by:

ME= \frac{54-46}{2}= 4

The confidence level is 0.96 and the significance level is \alpha=1-0.96=0.04 and the value of \alpha/2 =0.02 and the margin of error is given by:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

We can calculate the critical value and we got:

z_{\alpha/2} = 2.05

And if we solve for the deviation like this:

\sigma = ME * \frac{\sqrt{n}}{z_{\alpha/2}}

And replacing we got:

\sigma =4 *\frac{\sqrt{80}}{2.05} =17.45

Part b

For this case is the sample size is doubled the margin of error would be:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}=2.05 *\frac{17.45}{\sqrt{160}}=2.828

And as we can see that the margin of error would be lower than the original value of 4, the margin of error would be reduced by a factor \sqrt{2}

5 0
2 years ago
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