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lakkis [162]
3 years ago
12

A window is shaped like a rectangle whose perimeter is 182 in . The length is 6 times as long as the width. Find the length and

the width.
Mathematics
1 answer:
Murrr4er [49]3 years ago
6 0
P = 2L + 2W

182 = 2(6x) + 2x

Take it from here.
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A yoga membership costs $16 and an additional $7 per class. write a linear equation modeling the cost of a yoga membership.
MrRissso [65]
Y=16x+7
the x represents the number of memberships the 16 represents the cost of a membership and the 7 represents the additional cost.
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10 question please you don't have to do all I need help
andre [41]

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I'm sorry for not being able to help you but this kind of contents are not allowed ߷߷

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Write <img src="https://tex.z-dn.net/?f=%28-%20x%5E%7B2%7D%29%20-4x%2B2" id="TexFormula1" title="(- x^{2}) -4x+2" alt="(- x^{2})
marin [14]
Because the coefficient of x^2 is -1, we know that a will be -1.  Knowing that the coefficient of x is -4, we can calculate that p=2.  Thus, we have -1(x+2)^2+q is our equation.  This is equal to -x^2-4x-4+q.  As the constant term must be 2, we can then see that q is 6.

As such, we have -1(x+2)^2+6=0 as our factorization.

To solve this equation, we can use the quadratic formula.  Plugging in values, we have:

\frac{4+-2 \sqrt{6} }{-2}
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7 0
3 years ago
Three single-digit numbers multiply to make 504 Write the missing numbers
boyakko [2]
We will guess and check to solve this problem

504/9= 56
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3 0
3 years ago
Which of the following is not equal to sin⁡(-230°)?
xenn [34]

From trigonometry we know that:

if sin(\theta)=sin(\alpha)

then, \theta=n\pi+(-1)^n\alpha (where n is an integer)

This can be rewritten in degrees as:

\theta=n(180^{\circ})+(-1)^n\alpha.............(Equation 1)

Now, in our case, \alpha=-230^{\circ}

Therefore, (Equation 1) can be written as:

\theta=n(180^{\circ})+(-1)^n(-230^{\circ})..........(Equation 2)

Now, to find the correct options all that we have to do is replace n by relevant integers and find the values of \theta that match.

For n=2, (Equation 2) gives us: \theta=2\times 180^{\circ}+(-1)^2(-230^{\circ})=360^{\circ}-230^{\circ}=130^{\circ}.

Thus, sin(230^{\circ})=sin(130^{\circ})

Now, we know that: -sin(-50^{\circ})=sin(50^{\circ})

Let n=-1, then:

\theta=(-1)\times 180^{\circ}+(-1)^{-1}(-230^{\circ})=-180^{\circ}+230^{\circ}=50^{\circ}

Thus, sin(-230^{\circ})=-sin(-50^{\circ})

Likewise, sin(-230^{\circ})=sin(50^{\circ})

Only the last option sin(-50^{\circ}) will never match sin(-230^{\circ}) because no integral value of n will ever give \theta=-50^{\circ}

Thus the last option is the correct option.

3 0
3 years ago
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