FOR THE FIRST PROBLEM:
Differentiating p^2 + 2q^2 = 1100 with respect to time => 2p(dp/dt) + 4q(dq/dt) = 0
<span>dp/dt = -2q/p(dq/dt) </span>
<span>R = pq </span>
<span>dR/dt = p(dq/dt) + q(dp/dt) = -p²/2q(dp/dt) + q(dp/dt) = (2q² - 1100)/2q * (dp/dt) + q(dp/dt) </span>
<span>A = (2q - 550/q)
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Answer:
x = -1.14 or -13.14
Explanations:
The given equation is:
Find the half of 12, and add the square to both sides of the equation.
That is add 6² to both sides
Find the square root of both sides:
![\begin{gathered} \sqrt[]{(x+6)^2_{}}=\pm\sqrt[]{51} \\ \text{x + 6 = }\pm\sqrt[]{51} \\ x\text{ = -6 }\pm\sqrt[]{51} \\ \text{x = }-6\pm7.14 \\ x\text{ = -6+7.14 = }1.14 \\ x\text{ = -6 - 7.14} \\ \text{x = -13.14} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Csqrt%5B%5D%7B%28x%2B6%29%5E2_%7B%7D%7D%3D%5Cpm%5Csqrt%5B%5D%7B51%7D%20%5C%5C%20%5Ctext%7Bx%20%20%2B%20%206%20%20%3D%20%7D%5Cpm%5Csqrt%5B%5D%7B51%7D%20%5C%5C%20x%5Ctext%7B%20%20%3D%20%20-6%20%20%7D%5Cpm%5Csqrt%5B%5D%7B51%7D%20%5C%5C%20%5Ctext%7Bx%20%20%3D%20%7D-6%5Cpm7.14%20%5C%5C%20x%5Ctext%7B%20%20%3D%20-6%2B7.14%20%20%3D%20%7D1.14%20%5C%5C%20x%5Ctext%7B%20%3D%20-6%20-%207.14%7D%20%5C%5C%20%5Ctext%7Bx%20%3D%20-13.14%7D%20%5Cend%7Bgathered%7D)
x = -1.14 or -13.14
Answer:
-42 2/9
Step-by-step explanation:
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Answer:
=4/3
Step-by-step explanation:
Step 1
Multiply the denominator by the whole number
6 × 1 = 6
Step 2
Add the answer from Step 1 to the numerator
6 + 2 = 8
Step 3
Write answer from Step 2 over the denominator
8/6
=86
You can also reduce this fraction.
Find the Greatest Common Factor (GCF) of 8 and 6, if it exists, and reduce our fraction by dividing both numerator and denominator by it,
GCF = 2
=8÷2=4
6/2=3
Simplified Solution
=6×1+2/6 =8/6=4/3
hope this helps
you welcome and thanks
