Answer:
Step-by-step explanation:
Given that two fair dice are rolled 3 times and the sum of the numbers that come up is recorded.
a) The sum is 4 on each of the three rolls.
(1,3) (2,2) (3,1) HEnce for one throw prob = 3/36 =1/12
Prob for getting same sum 4 in 3 rolls = 
(since each trial is independent)
b) Prob sum =4 in exactly 2 rolls
= 
=
CEVAP:....................
Answer:
Option 'B' is correct.
Step-by-step explanation:
Since we have given that
Number of lemons used is denoted by 'y'.
Number of glasses of lemonade is denoted by 'x'.
As we can observe that ,
so we can write i as
By cross multiplication
<em>y=4x</em>
So, if write it in the form y=kx,
It will be y=4x.
You can use this formula <span>P(AorB) = P(A) + P(B) - P(AandB)
Given:
35 LG (14 F & 21 M)
44 SB (28 F & 16 M)
Req:
- the probability that it is a female (F) or a sky blue (SB)
Sol:
</span>P(F or SB) = P(F) + P(SB) - P(F and SB)
= [(14 F + 28 F)/(35 + 44)] + [(44 SB)/(35 + 44)] - [(28 F)/(35 + 44)]
= 53.16 + 55.70 - 35.44
= 73.42%
You have to deduct 28 female parakeets from 44 sky blue parakeets because the 28 parakeets are already accounted for in the female parakeets. You can also think of how many ways you can choose a female parakeet and a sky blue parakeet. Add all female parakeets (14 + 28) = 42. Sky blue parakeet equaled to 44. Minus the 28 female parakeets included in the sky blue parakeet to avoid double counting. 42 + 44 - 28 = 58 divided by 79 (35 + 44) total parakeets = 73.42%
