Which shows the graph of x – 4y = 4? Image for option 1 Image for option 2 Image for option 3 Image for option 4

Help its iready ill give brainiest

madam [21]

Answer:

7(1/2)

Step-by-step explanation:

7 0

3 years ago

1. Sally said that when you add or subtract positive or negative decimals, you can change the order of the decimals and still ge

gogolik [260]

ally’s answer is sometimes true. -6.2+5.71=-11.91 5.71+-6.2=11.91 5.72-2.84=2.99

7 0

3 years ago

Write a general formula to describe the variation: M varies jointly with the cube root of the difference B and b.

MAXImum [283]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\stackrel{\textit{M varies jointly with the cube root of the difference B and b}}{M=k\sqrt[3]{B-b}}$

8 0

3 years ago

A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent

kotykmax [81]

Answer:

Comparing the p value with the significance level $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.

Step-by-step explanation:

$\bar X_{1}=15$ represent the mean for sample 1

$\bar X_{2}=18$ represent the mean for sample 2

$s_{1}=5$ represent the sample standard deviation for 1

$s_{f}=6$ represent the sample standard deviation for 2

$n_{1}=49$ sample size for the group 2

$n_{2}=64$ sample size for the group 2

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}\neq 0$

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=49+64-2=111$

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897$

P value

Since is a bilateral test the p value would be:

$p_v =2*P(t_{111}$

Comparing the p value with the significance level $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.

7 0

3 years ago

A customer borrowed $2000 and then a further $1000 both repayble in 12 months. What would he have saved if he had taken out one

RSB [31]

A customer borrowed $2000 and then a further $1000 both repayble in 12 months. What would he have saved if he had taken out one loan for $3000 repayable in 12 months?

He took two different loans, it charged him loan processing fee twice, two-time documentation process, and of course, extra time spent for second loan. Instead, he could take single loan of $3000 with one-time processing fee, one-time documentation process, and time-saving also.

8 0

3 years ago