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grin007 [14]
3 years ago
8

Simplify the expression 6^3 + 5(4 - 2).2836226234​

Mathematics
2 answers:
valina [46]3 years ago
5 0

Answer:

226

Step-by-step explanation:

6^3 + 5(4 - 2)

PEMDAS says parentheses first

6^3 + 5(2)

Then exponents

216 +5(2)

Then multiply

216+10

Then add

226

ludmilkaskok [199]3 years ago
4 0

Answer:

226

Step-by-step explanation:

6^3 + 5(4 - 2)

BIMDAS says parentheses first

6^3 + 5(2)

Then indices

216 +5(2)

Then multiply

216+10

Then add

226

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the perimeter of a rectangle is 40m. one of the lengths or the sides is 5m. find the lengths of the other 3 sides.​
Annette [7]

The perimeter of a rectangle is 40m and one side of it is 5m. What is the length of the other side using an equation?

Perimeter of the rectangle =2(l+ b)=40m

If one of its side b=5, then l = (40/2)-5

= 20–5

= 15 m Therefore

Length= 15 cm

Breadth =5 cm

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Terrell Davids' charge account statement shows an unpaid balance of $110.00. The
faltersainse [42]

Answer:

Step-by-step explanation:

New Balance = 110 + 110*2/100

New Balance = 110 + 2.20

New Balance = 112.20

8 0
3 years ago
An article in Technometrics (Vol. 19, 1977, p. 425) presents the following data on the motor fuel octane ratings of several blen
Slav-nsk [51]

Answer:

Median = 90.4

Q_1 = 88.6

Q_3 = 92.2

Step-by-step explanation:

Given

The above data

Required

- A stem and leaf display

- The median

- The quartiles

First, determine the range of the data

Smallest = 83.4

Highest = 100.3

Next, group each dataset base on common whole numbers.

So, we have:

83.4

84.3\ 84.3

85.3

86.7\ 86.7\ 86.7

87.4\ 87.5\ 87.6\ 87.7\ 87.8\ 87.9

88.2\ 88.3\ 88.3\ 88.3\ 88.4\ 88.5\ 88.5\ 88.6\ 88.6\ 88.7\ 88.9

89.0\ 89.2\ 89.3\ 89.3\ 89.6\ 89.7\ 89.8\ 89.8\ 89.9\ 89.9

90.0\ 90.1\ 90.1\ 90.1\ 90.3\ 90.4\ 90.4\ 90.4\ 90.5\ 90.6\ 90.7\ 90.8\ 90.9

91.0\ 91.0\ 91.0\ 91.1\ 91.1\ 91.1\ 91.2\ 91.2\ 91.2\ \ 91.5\  91.6\ 91.6\ 91.8\ 91.8

92.2\ 92.2\ 92.2\ 92.3\ 92.6\ 92.7\ 92.7\ 92.7

93.0\ 93.2\ 93.3\ 93.3\ 93.4\ 93.7

94.2\ 94.2\ 94.4\ 94.7

96.1\ 96.5

98.8

100.3

Next, we construct the stem and leaf plot.

The whole numbers will be the stem while the decimal parts will be the leaf.

So, we have:

\begin{array}{ccc}{Stem} & {} & {Leaf} & {83} & {|} & {.4} & {84} & {|} & {.3\ .3} & {85} & {|} & {.3} & {86} & {|} & {.7\ .7\ .7} & {87} &{|} & {.4\ .5\ .6\ .7\ .8\ .9} & {88} & {|} & {.2\ .3\ .3\ .3\ .4\ .5\ .5\ .6\ .6\ .7\ .9} &{89} & {|} & {.0\ .2\ .3\ .3\ .6\ .7\ .8\ .8\ .9\ .9} & {90} & {|} &{.0\ .1\ .1\ .1\ .3\ .4\ .4\ .4\ .5\ .6\ .7\ .8\ .9} & {91} &{|}&{.0\ .0\ .0\ .1\ .1\ .1\ .2\ .2\ .2\ .5\ .6\ .6\ .8\ .8} &{92} &{|} &{.2\ .2\ .2\ .3\ .6\ .7\ .7\ .7} \ \end{array}

  \begin{array}{ccc} {93} & {|} & {.0\ .2\ .3\ .3\ .4\ .7} & {94} &{|} & {.2\ .2\ .4\ .7} &{96} & {|} & {.1\ .5} & {98} & {|} & {.8} & {100} &{|} &{.3} \ \end{array}

From the above plot,

n = 83

The median is calculated as:

Median = \frac{n+1}{2}th

Median = \frac{83+1}{2}th

Median = \frac{84}{2}th

Median = 42nd

i.e. the median is at the 42nd position.

From the above stem and leaf plot.

The 42nd position is at stem 90 and the leaf  .4

So the median is:

Median = 90.4

The lower quartile (Q) is calculated as:

Q_1 = \frac{n+1}{4}th

Q_1 = \frac{83+1}{4}th

Q_1 = \frac{84}{4}th

Q_1 = 21st

i.e. the lower quartile is at the 21st position.

From the above stem and leaf plot.

The 42nd position is at stem 88 and the leaf .6

So the lower quartile is:

Q_1 = 88.6

The upper quartile (Q3) is calculated as:

Q_3 = 3 * \frac{n+1}{4}th

Q_3 = 3 * \frac{83+1}{4}th

Q_3 = 3 * \frac{84}{4}th

Q_3 = 3 * 21th

Q_3 = 63rd

i.e. the upper quartile is at the 63rd position.

From the above stem and leaf plot.

The 63rd position is at stem 92 and the leaf .2

So the upper quartile is:

Q_3 = 92.2

8 0
3 years ago
Find the equation in standard form , of the line passing through points (2,-3) and (4,2)
Fudgin [204]

The form of linear equation that describes line is:

y=sx+n

First we must calculate the slope.

s=\dfrac{\Delta{y}}{\Delta{x}}=\dfrac{2-(-3)}{4-2}=\dfrac{5}{2}

Now it looks a bit more like this:

y=\dfrac{5}{2}x+n

All we need now is to put in y and x from one point doesn't matter which. I'll pick A.

The equation now looks like this:

-3=\dfrac{5}{2}\cdot2+n

Solve for n.

-3=5+n \\n=-8

And finally write the equation.

f(x)=\dfrac{5}{2}x-8

Hope this helps.

r3t40

7 0
3 years ago
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