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grin007 [14]
3 years ago
8

Simplify the expression 6^3 + 5(4 - 2).2836226234​

Mathematics
2 answers:
valina [46]3 years ago
5 0

Answer:

226

Step-by-step explanation:

6^3 + 5(4 - 2)

PEMDAS says parentheses first

6^3 + 5(2)

Then exponents

216 +5(2)

Then multiply

216+10

Then add

226

ludmilkaskok [199]3 years ago
4 0

Answer:

226

Step-by-step explanation:

6^3 + 5(4 - 2)

BIMDAS says parentheses first

6^3 + 5(2)

Then indices

216 +5(2)

Then multiply

216+10

Then add

226

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Divide. Write your answer in simplest form.<br> 7<br> — /8<br> 6
Zina [86]

Answer:

7/64

Step-by-step explanation:

7/6÷8=7/6*1/8=7/64

Hope this helps :)

5 0
3 years ago
Use the letters a, b, c, d, e, and f. write all possible selections of three letters that can be formed from the letters. (the o
tamaranim1 [39]
There are 6C3 = 20 such combinations.
abc, abd, abe, abf
acd, ace, acf, ade
adf, aef, bcd, bce
bcf, bde, bdf, bef
cde, cdf, cef, def
3 0
3 years ago
I Have To Find The Mode And Median.Explain What To Do Please
Pani-rosa [81]
To find the mean, add all the numbers, then divide by the amount of numbers there are. I'll do the first one as example.
6+5+6+9+9+11=46. 
46 divided by 6 = 7.66
To find the median, put all the numbers in order from biggest to smallest. 
5, 6, 6, 9, 9, 11.
Since there is an even amount of numbers, you have to add the two middle numbers (6,9) and divide by two. 
6+9= 15
15 divided by 2 = 7.5
To find the mode, you just have to find the most common number. In this case, there are two most common numbers (6,9) so the answer would be both. 
5,6,6,9,9,11
Answer:
Mean: 7.66
Median: 7.5
Mode: 6,9
7 0
3 years ago
Assume that adults have IQ scores that are normally distributed with a mean of mu equals 105 and a standard deviation sigma equa
kondor19780726 [428]

Answer:   0.6827

Step-by-step explanation:

Given : Mean IQ score : \mu=105

Standard deviation : \sigma=15

We assume that adults have IQ scores that are normally distributed .

Let x be the random variable that represents the IQ score of adults .

z-score : z=\dfrac{x-\mu}{\sigma}

For x= 90

z=\dfrac{90-105}{15}\approx-1

For x= 120

z=\dfrac{120-105}{15}\approx1

By using the standard normal distribution table , we have

The p-value : P(90

P(z

Hence,  the probability that a randomly selected adult has an IQ between 90 and 120 =0.6827

5 0
3 years ago
Read 2 more answers
What is 1.50 increased by 20%
ehidna [41]

p\%=\dfrac{p}{100}\\\\\text{increased by 20}\%\to100\%+20\%=120\%\\\\120\%=\dfrac{120}{100}=\dfrac{12}{10}=1.2\\\\1.50\ \text{increased by 20}\%\ \text{is the same as 120}\%\ \text{of}\ 1.50.\\\\120\%\ of\ 1.50\ is\ 1.2\cdot1.50=1.80\\\\Answer:\ \boxed{1.80}

3 0
4 years ago
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