Question

Write the point slope form of the line that passes through (-8,2) and is perpendicular to a line with a slope of -8

Answer 1

Answer:

$y - 2 = \frac{1}{8}(x +8)$

Step-by-step explanation:

Perpendicular lines have negative reciprocal slopes. Since the slope of one line is -8, its perpendicular line will have the slope of 1/8.

Substitute m = 1/8 and (-8,2) into the point slope form of a line.

$y - y_1 = m(x-x_1)\\y - 2 = \frac{1}{8}(x --8)\\y - 2 = \frac{1}{8}(x +8)$